I have written an AWS Lambda Handler as below :
package com.lambda;
import com.amazonaws.services.lambda.runtime.Context;
import com.amazonaws.services.lambda.runtime.LambdaLogger;
import com.amazonaws.services.lambda.runtime.RequestStreamHandler;
import java.io.*;
public class TestDetailsHandler implements RequestStreamHandler {
public void handleRequest(InputStream input,OutputStream output,Context context){
// Get Lambda Logger
LambdaLogger logger = context.getLogger();
// Receive the input from Inputstream throw exception if any
File starting = new File(System.getProperty("user.dir"));
System.out.println("Source Location" + starting);
File cityFile = new File(starting + "City.db");
FileInputStream fis = null;
try {
fis = new FileInputStream(cityFile);
System.out.println("Total file size to read (in bytes) : "
+ fis.available());
int content;
while ((content = fis.read()) != -1) {
// convert to char and display it
System.out.print((char) content);
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
if (fis != null)
fis.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}
}
}
Its read a file : City.db , available in resources folder, even I kept to everywhere see below :
But it showing following message on execution of this lambda function :
START RequestId: 5216ea47-fc43-11e5-96d5-83c1dcdad75d Version: $LATEST
Source Location/
java.io.FileNotFoundException: /city.db (No such file or directory)
at java.io.FileInputStream.open0(Native Method)
at java.io.FileInputStream.open(FileInputStream.java:195)
at java.io.FileInputStream.<init>(FileInputStream.java:138)
at com.lambda.TestDetailsHandler.handleRequest(TestDetailsHandler.java:26)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:497)
at lambdainternal.EventHandlerLoader$StreamMethodRequestHandler.handleRequest(EventHandlerLoader.java:511)
at lambdainternal.EventHandlerLoader$2.call(EventHandlerLoader.java:972)
at lambdainternal.AWSLambda.startRuntime(AWSLambda.java:231)
at lambdainternal.AWSLambda.<clinit>(AWSLambda.java:59)
at java.lang.Class.forName0(Native Method)
at java.lang.Class.forName(Class.java:348)
at lambdainternal.LambdaRTEntry.main(LambdaRTEntry.java:93)
END RequestId: 5216ea47-fc43-11e5-96d5-83c1dcdad75d
REPORT RequestId: 5216ea47-fc43-11e5-96d5-83c1dcdad75d Duration: 58.02 ms Billed Duration: 100 ms Memory Size: 1024 MB Max Memory Used: 50 MB
Contents of the Pom.xml file :
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.lambda</groupId>
<artifactId>testdetails</artifactId>
<version>1.0-SNAPSHOT</version>
<packaging>jar</packaging>
<name>test-handler</name>
<dependencies>
<dependency>
<groupId>com.amazonaws</groupId>
<artifactId>aws-lambda-java-core</artifactId>
<version>1.1.0</version>
</dependency>
<dependency>
<groupId>junit</groupId>
<artifactId>junit</artifactId>
<version>4.11</version>
<scope>test</scope>
</dependency>
</dependencies>
<build>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-shade-plugin</artifactId>
<version>2.3</version>
<configuration>
<createDependencyReducedPom>false</createDependencyReducedPom>
</configuration>
<executions>
<execution>
<phase>package</phase>
<goals>
<goal>shade</goal>
</goals>
</execution>
</executions>
</plugin>
</plugins>
</build>
</project>
I have used various ways to keep file here and there , but at the end its not working. May you please let me know what is wrong here ?
However in my another project where I have kept xyz.properties file in resources folder and reading from a PropertyManager file, its working fine. When I tested it on my system its working fine, but on AWS Lambda function it doesn't work.
You can run Java code in AWS Lambda. Lambda provides runtimes for Java that run your code to process events. Your code runs in an Amazon Linux environment that includes AWS credentials from an AWS Identity and Access Management (IAM) role that you manage.
Lambda supports two types of deployment packages: container images and . zip file archives. This page describes how to create your deployment package as a . zip file or Jar file, and then use the deployment package to deploy your function code to AWS Lambda using the AWS Command Line Interface (AWS CLI).
I have made following changes in my code and now its works perfect :
Majorly changed following two lines :
ClassLoader classLoader = getClass().getClassLoader();
File cityFile = new File(classLoader.getResource("City.db").getFile());
package com.lambda;
import com.amazonaws.services.lambda.runtime.Context;
import com.amazonaws.services.lambda.runtime.LambdaLogger;
import com.amazonaws.services.lambda.runtime.RequestStreamHandler;
import java.io.*;
public class TestDetailsHandler implements RequestStreamHandler {
public void handleRequest(InputStream input,OutputStream output,Context context){
// Get Lambda Logger
LambdaLogger logger = context.getLogger();
// Receive the input from Inputstream throw exception if any
ClassLoader classLoader = getClass().getClassLoader();
File cityFile = new File(classLoader.getResource("City.db").getFile());
FileInputStream fis = null;
try {
fis = new FileInputStream(cityFile);
System.out.println("Total file size to read (in bytes) : "
+ fis.available());
int content;
while ((content = fis.read()) != -1) {
// convert to char and display it
System.out.print((char) content);
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
if (fis != null)
fis.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}
}
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