I have an integer x
and I want to check if it lies between a given boundary / within a given range.
The straightforward approach would be
let contains = x > lowerBounds && x < higherBounds
Is there a more swifty approach to this?
ValueRange. of(minValue, maxValue); range. isValidIntValue(x); it returns true if minValue <= x <= MaxValue - i.e. within the range.
You can check if a number is present or not present in a Python range() object. To check if given number is in a range, use Python if statement with in keyword as shown below. number in range() expression returns a boolean value: True if number is present in the range(), False if number is not present in the range.
You can create a range and check if it contains x
:
let contains = (lowerBounds...upperBounds).contains(x)
e.g.:
let successful = (200..<300).contains(httpStatusCode)
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With