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How to query on subset of composite primary key?

I have the following classes:

@Entity
@Table(name = "my_entity")
@JsonIgnoreProperties(ignoreUnknown = true)
public class MyEntity {
    @EmbeddedId
    private Pk id;

    public Pk getId() {
        return id;
    }

    public void setId(Pk id) {
        this.id = id;
    }

}

@Embeddable
public class Pk implements Serializable {
    private static final long serialVersionUID = -3090221844117493661L;
    private Integer type;
    private String userId;

    public Pk() {
    }

    public Pk(String userId, Integer type) {
        this.setUserId(userId);
        this.setType(type);
    }

    public Integer getType() {
        return type;
    }

    public String getUserId() {
        return userId;
    }

    public void setType(Integer type) {
        this.type = type;
    }

    public void setUserId(String userId) {
        this.userId = userId;
    }

    // Auto-generated by Eclipse.
    @Override
    public int hashCode() {
        final int prime = 31;
        int result = 1;
        result = prime * result + ((type == null) ? 0 : type.hashCode());
        result = prime * result + ((userId == null) ? 0 : userId.hashCode());
        return result;
    }

    // Auto-generated by Eclipse.
    @Override
    public boolean equals(Object obj) {
        if (this == obj)
            return true;
        if (obj == null)
            return false;
        if (getClass() != obj.getClass())
            return false;
        Pk other = (Pk) obj;
        if (type != other.type)
            return false;
        if (userId == null) {
            if (other.userId != null)
                return false;
        } else if (!userId.equals(other.userId))
            return false;
        return true;
    }

}

public interface MyEntityRepository extends JpaRepository<MyEntity, Pk> {

    List<MyEntity> findAllByUserId(String userId);

}

When I initialize Spring Data JPA I am getting the error:

Exception in thread "main" org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'myEntityRepository': Invocation of init method failed; nested exception is org.springframework.data.mapping.PropertyReferenceException: No property user found for type MyEntity!
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1512)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:521)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:458)
    at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:296)
    at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:223)
    at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:293)
    at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:194)
    at org.springframework.beans.factory.support.DefaultListableBeanFactory.preInstantiateSingletons(DefaultListableBeanFactory.java:615)
    at org.springframework.context.support.AbstractApplicationContext.finishBeanFactoryInitialization(AbstractApplicationContext.java:932)
    at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:479)
    at org.springframework.context.annotation.AnnotationConfigApplicationContext.<init>(AnnotationConfigApplicationContext.java:73)
    at com.myproject.backend.common.ServiceContext.start(ServiceContext.java:293)
    at com.myproject.run(AbstractServiceContainer.java:55)
    at com.myproject..run(AbstractServiceContainer.java:1)
    at io.dropwizard.cli.EnvironmentCommand.run(EnvironmentCommand.java:42)
    at io.dropwizard.cli.ConfiguredCommand.run(ConfiguredCommand.java:76)
    at io.dropwizard.cli.Cli.run(Cli.java:70)
    at io.dropwizard.Application.run(Application.java:72)
    at com.myproject..main(CombinedServiceContainer.java:106)
Caused by: org.springframework.data.mapping.PropertyReferenceException: No property user found for type MyEntity!
    at org.springframework.data.mapping.PropertyPath.<init>(PropertyPath.java:75)
    at org.springframework.data.mapping.PropertyPath.create(PropertyPath.java:327)
    at org.springframework.data.mapping.PropertyPath.create(PropertyPath.java:359)
    at org.springframework.data.mapping.PropertyPath.create(PropertyPath.java:307)
    at org.springframework.data.mapping.PropertyPath.from(PropertyPath.java:270)
    at org.springframework.data.mapping.PropertyPath.from(PropertyPath.java:241)
    at org.springframework.data.repository.query.parser.Part.<init>(Part.java:76)
    at org.springframework.data.repository.query.parser.PartTree$OrPart.<init>(PartTree.java:213)
    at org.springframework.data.repository.query.parser.PartTree$Predicate.buildTree(PartTree.java:321)
    at org.springframework.data.repository.query.parser.PartTree$Predicate.<init>(PartTree.java:301)
    at org.springframework.data.repository.query.parser.PartTree.<init>(PartTree.java:85)
    at org.springframework.data.jpa.repository.query.PartTreeJpaQuery.<init>(PartTreeJpaQuery.java:60)
    at org.springframework.data.jpa.repository.query.JpaQueryLookupStrategy$CreateQueryLookupStrategy.resolveQuery(JpaQueryLookupStrategy.java:91)
    at org.springframework.data.jpa.repository.query.JpaQueryLookupStrategy$CreateIfNotFoundQueryLookupStrategy.resolveQuery(JpaQueryLookupStrategy.java:168)
    at org.springframework.data.jpa.repository.query.JpaQueryLookupStrategy$AbstractQueryLookupStrategy.resolveQuery(JpaQueryLookupStrategy.java:69)
    at org.springframework.data.repository.core.support.RepositoryFactorySupport$QueryExecutorMethodInterceptor.<init>(RepositoryFactorySupport.java:320)
    at org.springframework.data.repository.core.support.RepositoryFactorySupport.getRepository(RepositoryFactorySupport.java:169)
    at org.springframework.data.repository.core.support.RepositoryFactoryBeanSupport.initAndReturn(RepositoryFactoryBeanSupport.java:224)
    at org.springframework.data.repository.core.support.RepositoryFactoryBeanSupport.afterPropertiesSet(RepositoryFactoryBeanSupport.java:210)
    at org.springframework.data.jpa.repository.support.JpaRepositoryFactoryBean.afterPropertiesSet(JpaRepositoryFactoryBean.java:92)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1571)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1509)
    ... 18 more

Question: Does Spring Data JPA not support querying on a subset of a primary key? Or will I need to implement a custom repository method for this?

like image 922
Ztyx Avatar asked Jan 19 '15 08:01

Ztyx


2 Answers

You need to tell JPA where to look for the userId field (in the embedded id, that is). If you change the name of the repository method to findAllByIdUserId, it should work.

like image 57
Stefan Frye Avatar answered Oct 18 '22 06:10

Stefan Frye


Okay, I also tried doing this with @IdClass instead:

@Entity
@Table(name = "my_entity")
@JsonIgnoreProperties(ignoreUnknown = true)
@IdClass(Pk.class)
public class MyEntity {
    @Id private Integer type;
    @Id private String userId;

    public Pk getId() {
        return id;
    }

    public void setId(Pk id) {
        this.id = id;
    }

}

@IdClass(Pk.class)
public class Pk implements Serializable {
    private static final long serialVersionUID = -3090221844117493661L;
    private Integer type;
    private String userId;

    public Pk() {
    }

    public Pk(String userId, Integer type) {
        this.setUserId(userId);
        this.setType(type);
    }

    public Integer getType() {
        return type;
    }

    public String getUserId() {
        return userId;
    }

    public void setType(Integer type) {
        this.type = type;
    }

    public void setUserId(String userId) {
        this.userId = userId;
    }

    // Auto-generated by Eclipse.
    @Override
    public int hashCode() {
        final int prime = 31;
        int result = 1;
        result = prime * result + ((type == null) ? 0 : type.hashCode());
        result = prime * result + ((userId == null) ? 0 : userId.hashCode());
        return result;
    }

    // Auto-generated by Eclipse.
    @Override
    public boolean equals(Object obj) {
        if (this == obj)
            return true;
        if (obj == null)
            return false;
        if (getClass() != obj.getClass())
            return false;
        Pk other = (Pk) obj;
        if (type != other.type)
            return false;
        if (userId == null) {
            if (other.userId != null)
                return false;
        } else if (!userId.equals(other.userId))
            return false;
        return true;
    }

}

This did gave me a different error message, a NullPointerException, that was hinting to me that Spring Data JPA was unable to build the query for findAllByUserId(...). I made a custom implementation of that query method instead:

public interface MyEntityRepository extends JpaRepository<MyEntity, Pk>, MyEntityRepositoryCustom {

}

public interface MyEntityRepositoryCustom {

    List<MyEntity> findAllByUserId(String userId);

}

public class MyEntityRepositoryImpl implements MyEntityRepositoryCustom {

    @PersistenceContext
    private EntityManager em;

    @Override
    public List<MyEntityRepositoryCustom> findAllByUserId(String userId) {
        return em
                .createQuery("select o from MyEntity o where o.userId=:userId",
                        MyEntity.class).setParameter("userId", userId).getResultList();
    }

}

...and voilá, it works!

like image 30
Ztyx Avatar answered Oct 18 '22 06:10

Ztyx