Note
has a many-to-many relationship to Subject
What is the best way to query it? I would like to write the following to get all the subjects on a give note:
const subjectRepo = connection.getRepository(Subject); const response = await subjectRepo.find({ relations: ['notes'], where: { note } });
but that returns ALL of the subjects, not just the subjects on the note.
Reln defined as:
@ManyToMany(() => Subject, (subject: Subject) => subject.notes) subjects: Subject[];
-- and --
@ManyToMany(() => Note, note => note.subjects) @JoinTable() notes: Note[];
The executed query is:
SELECT "Subject"."id" AS "Subject_id", "Subject"."name" AS "Subject_name", "Subject"."description" AS "Subject_description", "Subject"."createdDate" AS "Subject_createdDate", "Subject"."updatedDate" AS "Subject_updatedDate", "Subject"."notebookId" AS "Subject_notebookId", "Subject"."measurementsId" AS "Subject_measurementsId", "Subject_notes"."id" AS "Subject_notes_id", "Subject_notes"."content" AS "Subject_notes_content", "Subject_notes"."notedAt" AS "Subject_notes_notedAt", "Subject_notes"."createdDate" AS "Subject_notes_createdDate", "Subject_notes"."updatedDate" AS "Subject_notes_updatedDate", "Subject_notes"."notebookId" AS "Subject_notes_notebookId" FROM "subject" "Subject" LEFT JOIN "subject_notes_note" "Subject_Subject_notes" ON "Subject_Subject_notes"."subjectId"="Subject"."id" LEFT JOIN "note" "Subject_notes" ON "Subject_notes"."id"="Subject_Subject_notes"."noteId"
Note: you can do this:
return subjectRepo .createQueryBuilder('subject') .leftJoin('subject.notes', 'note') .where('note.id = :id', { id: note.id }) .getMany();
But I am hoping for an approach with less strings, and explicit joining
Many-to-many is a relation where A contains multiple instances of B, and B contain multiple instances of A. Let's take for example Question and Category entities. A question can have multiple categories, and each category can have multiple questions. @JoinTable() is required for @ManyToMany relations.
To delete a many-to-many relationship between two records, remove it from the corresponding field and save the record. This will only remove the record in the join table.
The SQL you are trying to get TypeORM to generate is roughly as follows
SELECT * FROM subject JOIN subject_note AS jt on jt.subject_id = subject.id WHERE jt.note_id = :id
repo.find
At the time of writing, there is no way to create a where
clause on a joined table using repo.find(...)
. You can join
(doc) but the where
clause only affects the entity of the repository.
TypeORM
also silently ignores invalid where clauses, so be careful about those.
If you want all the subject
of a given note
, you will either need to use a query builder, like you noted or you will need to re-select the note object with it's relationships.
note = await noteRepo.find({ relations: ['subjects'], where: { id: note.id } }); const subjects = note.subjects
TypeORM
lazy relationsIf you want to avoid re-selection, you need to use TypeORM
Lazy relations but this forces you to change the type in both entities to be a Promise
// note entity @ManyToMany(() => Subject, (subject: Subject) => subject.notes) subjects: Promise<Subject[]>; // subject entity @ManyToMany(() => Note, note => note.subjects) @JoinTable() notes: Promise<Note[]>;
With this lazy relations, you will need to await
for the linked notes to load before each usage, but you will not need to provide an array of relations to the find
method.
const note = await noteRepo.find({ where: { id: someId } }); const subjects = await note.subjects
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