How to printf long long

Question

I'm doing a program that aproximate PI and i'm trying to use long long, but it isn't working. Here is the code

#include<stdio.h> #include<math.h> typedef long long num; main(){     num pi;     pi=0;     num e, n;     scanf("%d", &n);     for(e=0; 1;e++){       pi += ((pow((-1.0),e))/(2.0*e+1.0));       if(e%n==0)         printf("%15lld -> %1.16lld\n",e, 4*pi);       //printf("%lld\n",4*pi);     } } 

Answer 1

%lld is the standard C99 way, but that doesn't work on the compiler that I'm using (mingw32-gcc v4.6.0). The way to do it on this compiler is: %I64d

So try this:

if(e%n==0)printf("%15I64d -> %1.16I64d\n",e, 4*pi); 

and

scanf("%I64d", &n); 

The only way I know of for doing this in a completely portable way is to use the defines in <inttypes.h>.

In your case, it would look like this:

scanf("%"SCNd64"", &n); //...     if(e%n==0)printf("%15"PRId64" -> %1.16"PRId64"\n",e, 4*pi); 

It really is very ugly... but at least it is portable.