This is basically what I am trying to do
// ... some code, calculations, what have you ...
long timeToAdd = returnTimeToAddInLongFormat();
// lets output the long type now, and yes i need the width and precision.
System.out.printf("Time to add: %13.10ld", timeToAdd);
I've read most of the google searches around the topic and think I understand how to do it conceptually, but the JRE keeps throwing me a UnknownFormatConversionException
and telling me my input size modifier l
doesnt work.
Is there another way to do this, or did I miss something small?
To print a long value, use the %ld format specifier. You can use the l prefix for x and o, too. So you would use %lx to print a long integer in hexadecimal format and %lo to print in octal format. C allows both uppercase and lowercase letters for constant suffixes, these format specifiers use just lowercase.
Long Int Format Specifier %ld The %ld format specifier is implemented for representing long integer values. It is implemented with the printf() function for printing the long integer value stored in the variable.
%ul will just print unsigned (with %u), and then the letter "l" verbatim. Just as "%uw" will print unsigned, followed by letter "w".
We should use “%zu” to print the variables of size_t length. We can use “%d” also to print size_t variables, it will not show any error. The correct way to print size_t variables is use of “%zu”.
Java treats all integer values as d
, there is no ld. Even byte and BigInteger is a d
type. It also assumes integers have no decimal places. If you want to show 10 zeros, you can convert to double first and use f
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