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I'd like to print list item with the index of item such as
0: [('idx', 10), ('degree', 0)]
1: [('idx', 20), ('degree', 0)]
Based on the code below, how can I append '0:' as integer + string + list item?
import logging
class Node(object):
__slots__= "idx", "degree"
def __init__(self, idx, degree):
self.idx = idx
self.degree = 0
def items(self):
"dict style items"
return [
(field_name, getattr(self, field_name))
for field_name in self.__slots__]
def funcA():
a = []
a.append(Node(10, 0))
a.append(Node(20, 0))
for i in range(0, len(a)):
logging.debug(a[i].items())
if __name__ == '__main__':
logging.basicConfig(level=logging.DEBUG)
funcA()
Currently, result is
DEBUG:root:[('idx', 10), ('degree', 0)]
DEBUG:root:[('idx', 20), ('degree', 0)]
Expecting
DEBUG:root:0:[('idx', 10), ('degree', 0)]
DEBUG:root:1:[('idx', 20), ('degree', 0)]
814
Python - Print Logs in a File. If you want to print python logs in a file rather than on the console then we can do so using the basicConfig() method by providing filename and filemode as parameter. The format of the message can be specified by using format parameter in basicConfig() method.
Without using loops: * symbol is use to print the list elements in a single line with space. To print all elements in new lines or separated by space use sep=”\n” or sep=”, ” respectively.
You can only use log() with a single number. So you'll need to write a loop to iterate over your list and apply log() to each number. If you have a list of pressures you want the log of already produced, and given log() is the complete operation, I'm partial towards pressures_log = map(log, pressures) .
logger = logging.getLogger(__name__) This means that logger names track the package/module hierarchy, and it's intuitively obvious where events are logged just from the logger name. Sounds like good advice.
with Python > 3.6 you can use fstring
logging.debug(f"{i}:{a[i].items()}")
I would do it like this.
def funcA():
a = []
a.append(Node(10, 0))
a.append(Node(20, 0))
for i in range(0, len(a)):
message = '%s:%s' % (i, a[i].items())
logging.debug(message)
Which produces this as output:
DEBUG:root:0:[('idx', 10), ('degree', 0)]
DEBUG:root:1:[('idx', 20), ('degree', 0)]
You could also use join:
message = ':'.join([str(i), str(a[i].items())])
Or format:
message = '{0}:{1}'.format(str(i), a[i].items())
Whatever is the most clear to you.
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