How to print each item of list in separate line clojure?

Question

I'm very new in clojure. I want to print each item of list in newline. I'm trying like this:

user=> (def my-list '(1 2 3 4 5 ))
;; #'user/my-list
user=> my-list
;; (1 2 3 4 5)
user=> (apply println my-list)
;; 1 2 3 4 5
;; nil

But I want my output must be:

1
2
3
4
5
nil

can anyone tell me, How can I do this? Thanks.

Answer 1

If you already have a function that you would like to apply to every item in a single sequence, you can use run! instead of doseq for greater concision:

(run! println [1 2 3 4 5])
;; 1
;; 2
;; 3
;; 4
;; 5
;;=> nil

doseq is useful when the action you want to perform is more complicated than just applying a single function to items in a single sequence, but here run! works just fine.

Answer 2

This kind of use case (perform a side effect once for each member of a sequence) is the purpose of doseq. Using it here would be like

(doseq [item my-list]
   (println item))

Note that this will not print nil but will return it. Working with it in the REPL will see the return values of all expressions printed, but doesn't happen in e.g. starting your project as a terminal program.