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try: something here except: print('the whatever error occurred.') How can I print the error/exception in my except: block?
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To catch and print an exception that occurred in a code snippet, wrap it in an indented try block, followed by the command "except Exception as e" that catches the exception and saves its error message in string variable e . You can now print the error message with "print(e)" or use it for further processing.
Catching Exceptions in Python In Python, exceptions can be handled using a try statement. The critical operation which can raise an exception is placed inside the try clause. The code that handles the exceptions is written in the except clause.
Print Stack Trace in Python Using traceback Module The traceback. format_exc() method returns a string that contains the information about exception and stack trace entries from the traceback object. We can use the format_exc() method to print the stack trace with the try and except statements.
For Python 2.6 and later and Python 3.x:
except Exception as e: print(e) For Python 2.5 and earlier, use:
except Exception,e: print str(e) The traceback module provides methods for formatting and printing exceptions and their tracebacks, e.g. this would print exception like the default handler does:
import traceback try: 1/0 except Exception: traceback.print_exc() Output:
Traceback (most recent call last): File "C:\scripts\divide_by_zero.py", line 4, in <module> 1/0 ZeroDivisionError: division by zero If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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