How to print 64-bit integer in GCC 4.4.1?

Question

I am using Code::Blocks with GCC 4.4.1 and I seem to be unable to print 64-bit signed integers from my C-code.

This code:

long long longint;

longint = 0x1BCDEFABCDEFCDEF; /* 2003520930423229935 */
printf("Sizeof: %d-bit\n", sizeof(longint) * 8);     /* Correct */
printf("%llx\n", longint);                           /* Incorrect */
printf("%x%x\n", *(((int*)(&longint))+1), longint);  /* Correct */
printf("%lld\n", longint);                           /* Incorrect */ 

Produces output:

Sizeof: 64-bit
cdefcdef
1bcdefabcdefcdef
-839922193

64-bit arithmetic seems to work correctly:

longint -= 0x1000000000000000;
printf("%x%x\n", *(((int*)(&longint))+1), longint);

Gives:

bcdefabcdefcdef

Am I missing something?

Answer 1

To (in C99 and up) portably print 64 bit integers, you should #include <inttypes.h> and use the C99 macros PRIx64 and PRId64. That would make your code;

printf("Sizeof: %d-bit\n", sizeof(longint) * 8);
printf("%" PRIx64 "\n", longint);
printf("%" PRId64 "\n", longint);

Edit: See this question for more examples.

Answer 2

longint = 0x1BCDEFABCDEFCDEF; /* 2003520930423229935 */ you can print as-

printf("%llx", longint);