I am trying to print numbers from 1 to 100 without using loops, using C#. Any clues?
Example Code h> main() { int n; char *arr[2] = {"Even", "Odd"}; printf("Enter a number: "); //take the number from the user scanf("%d", &n); (n & 1 && printf("odd"))|| printf("even"); //n & 1 will be 1 when 1 is present at LSb, so it is odd. }
No loops, no conditionals, and no hardcoded literal output, aka "divide and conquer FTW" solution:
class P
{
static int n;
static void P1() { System.Console.WriteLine(++n); }
static void P2() { P1(); P1(); }
static void P4() { P2(); P2(); }
static void P8() { P4(); P4(); }
static void P16() { P8(); P8(); }
static void P32() { P16(); P16(); }
static void P64() { P32(); P32(); }
static void Main() { P64(); P32(); P4(); }
}
Alternative approach:
using System;
class C
{
static int n;
static void P() { Console.WriteLine(++n); }
static void X2(Action a) { a(); a(); }
static void X5(Action a) { X2(a); X2(a); a(); }
static void Main() { X2(() => X5(() => X2(() => X5(P)))); }
}
Console.Out.WriteLine('1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,90,91,92,93,94,95,96,97,98,99,100');
Recursion maybe?
public static void PrintNext(i) {
if (i <= 100) {
Console.Write(i + " ");
PrintNext(i + 1);
}
}
public static void Main() {
PrintNext(1);
}
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