How to prevent keypress two digits after a decimal number?

Question

I have got a task to prevent keypress two digits after a decimal number. My jquery file is

$(function(){ 
    $('#name').bind('paste', function(){
    var self = this;
    setTimeout(function() {
        if(!/^[a-zA-Z]+$/.test($(self).val()))
            $(self).val('');
    }, 0);    
           }); 

        $('#salary').bind('paste', function(){
    var self = this;
    setTimeout(function() {
        if(!/^\d*(\.\d{1,2})+$/.test($(self).val()))
            $(self).val('');
    }, 0);    
           }); 

    $('.decimal').keyup(function(){
        var val = $(this).val();
        if(isNaN(val)){
             val = val.replace(/[^0-9]./g,'');


             if(val.split('.').length>2) 
                 val =val.replace(/\.+$/,"");
        }
        $(this).val(val); 
    });
    });      

My html page is

<b>Name</b>
<input type="text" id="name"  /><br/>
<b>Salary</b>
<input type="text" id="salary"  class="decimal" />

here i want only write 2 digits after decimal,how can i do this? You can see my code in http://jsfiddle.net/V6s4B/

Answer 1

You can handle the key event before keyup on keypress, if the input is not to our liking we can disable the event from occurring. Something like this:

Update

Unfortunately my original answer below fails on certain numbers that can't be represented accurately as a float. Here is another solution that checks the position of the '.' character against the length of the string with a handy helper function.

jsFiddle

$('.decimal').keypress(function (e) {
    var character = String.fromCharCode(e.keyCode)
    var newValue = this.value + character;
    if (isNaN(newValue) || hasDecimalPlace(newValue, 3)) {
        e.preventDefault();
        return false;
    }
});

function hasDecimalPlace(value, x) {
    var pointIndex = value.indexOf('.');
    return  pointIndex >= 0 && pointIndex < value.length - x;
}

Original answer

jsFiddle

$('.decimal').keypress(function (e) {
    var character = String.fromCharCode(e.keyCode)
    var newValue = this.value + character;
    if (isNaN(newValue) || parseFloat(newValue) * 100 % 1 > 0) {
        e.preventDefault();
        return false;
    }
});

Note that parseFloat(newValue) * 100 % 1 > 0 evaluates to true if newValue contains a number that has more than 2 decimal places.

Answer 2

$("#salary").keyup(function(){
    var number = ($(this).val().split('.'));
    if (number[1].length > 2)
    {
        var salary = parseFloat($("#salary").val());
        $("#salary").val( salary.toFixed(2));
    }
  });

http://jsfiddle.net/calder12/fSQpc/

Stop letters from going in the box, you'll have to put the two together I haven't time.

    if (this.value.match(/[^0-9]./g)) {
      this.value = this.value.replace(/[^0-9]./g, '');
      return false;
    }