How to prevent crashing when Guzzle detect 400 or 500 error?

Question

I'm using PHP guzzle

I have tried

public static function get($url) {

    $client = new Client();

    try {
        $res = $client->request('GET',$url);
        $result = (string) $res->getBody();
        $result = json_decode($result, true);
        return $result;
    }
    catch (GuzzleHttp\Exception\ClientException $e) {
        $response = $e->getResponse();
        $responseBodyAsString = $response->getBody()->getContents();
    }

}

I kept getting

How to prevent crashing when Guzzle detecct 400 or 500 error ?

I just want my application to continue running and loading.

Answer 1

So, I'd bet your get() function exists in a namespace like App\Http\Controllers, which means this:

catch (GuzzleHttp\Exception\ClientException $e) {

is actually being interpreted as if you'd written:

catch (App\Http\Controllers\GuzzleHttp\Exception\ClientException $e) {

For obvious reasons, no exception of that kind is being thrown.

You can fix the namespacing issue by doing:

catch (\GuzzleHttp\Exception\ClientException $e) {

(note the leading \) or putting:

use GuzzleHttp\Exception\ClientException;

at the top of the file after the namespace declaration and catching just ClientException.

See http://php.net/manual/en/language.namespaces.basics.php.

Answer 2

Also take a look at http_errors option to disable exceptions at all (if for your application it's an expected scenario, and you want to handle all responses specifically by yourself).