I need to send data by POST method.
For example, I have the string "bla&bla&bla". I tried using encodeURI
and got "bla&bla&bla" as the result. I need to replace "&" with something correct for this example.
What kind of method should I call to prepare correct POST data?
UPDATED:
I need to convert only charachters which may broke POST request. Only them.
In order to encode/decode a string in JavaScript, We are using built-in functions provided by JavaScript. btoa(): This method encodes a string in base-64 and uses the “A-Z”, “a-z”, “0-9”, “+”, “/” and “=” characters to encode the provided string.
General Answer. The general answer to your question is that it depends. And you get to decide by specifying what your "Content-Type" is in the HTTP headers. A value of "application/x-www-form-urlencoded" means that your POST body will need to be URL encoded just like a GET parameter string.
URLEncode() function. In JavaScript you can use the encodeURIComponent() function. Click the "URL Encode" button to see how the JavaScript function encodes the text. Note: The JavaScript function encodes space as %20.
Decoding in Javascript can be achieved using decodeURI function. It takes encodeURIComponent(url) string so it can decode these characters. 2. unescape() function: This function takes a string as a single parameter and uses it to decode that string encoded by the escape() function.
>>> encodeURI("bla&bla&bla")
"bla&bla&bla"
>>> encodeURIComponent("bla&bla&bla")
"bla%26bla%26bla"
You can also use escape()
function.The escape()
function encodes a string.
This function makes a string portable, so it can be transmitted across any network to any computer that supports ASCII characters.This function encodes special characters, with the exception of: * @ - _ + . /
var queryStr = "bla&bla&bla";
alert(queryStr); //bla&bla&bla
alert(escape(queryStr)); //bla%26bla%26bla
Use unescape()
to decode a string.
var newQueryStr=escape(queryStr);
alert(unescape(newQueryStr)); //bla&bla&bla
Note:
escape() will not encode: @*/+
encodeURI() will not encode: ~!@#$&*()=:/,;?+'
encodeURIComponent() will not encode: ~!*()'
After some search on internet, I got the following:
escape()
Don't use it.
encodeURI()
Use encodeURI when you want a working URL. Make this call:
encodeURI("http://www.google.com/a file with spaces.html")
to get:
http://www.google.com/a%20file%20with%20spaces.html
Don't call encodeURIComponent since it would destroy the URL and return
http%3A%2F%2Fwww.google.com%2Fa%20file%20with%20spaces.html
encodeURIComponent()
Use encodeURIComponent when you want to encode a URL parameter.
param1 = encodeURIComponent("http://xyz.com/?a=12&b=55")
Then you may create the URL you need:
url = "http://domain.com/?param1=" + param1 + "¶m2=99";
And you will get this complete URL:
http://www.domain.com/?param1=http%3A%2F%2Fxyz.com%2F%Ffa%3D12%26b%3D55¶m2=99
Note that encodeURIComponent
does not escape the ' character. A common bug is to use it to create html attributes such as href='MyUrl',
which could suffer an injection bug. If you are constructing html from strings, either use " instead of ' for attribute quotes, or add an extra layer of encoding (' can be encoded as %27).
REF:When are you supposed to use escape instead of encodeURI / encodeURIComponent?
Also, as you are using JQuery, take a look at this built-in function.
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