I am trying to find the optimal solution to the follow system of equations in Python:
(x-x1)^2 + (y-y1)^2 - r1^2 = 0
(x-x2)^2 + (y-y2)^2 - r2^2 = 0
(x-x3)^2 + (y-y3)^2 - r3^2 = 0
Given the values a point(x,y) and a radius (r):
x1, y1, r1 = (0, 0, 0.88)
x2, y2, r2 = (2, 0, 1)
x3, y3, r3 = (0, 2, 0.75)
What is the best way to find the optimal solution for the point (x,y)
Using the above example it would be:
~ (1, 1)
Getting readyMake a new folder in your Desktop called scipy-optimize . Download scipy-optimize-data. zip and move the file to this folder. If it's not unzipped yet, double-click on it to unzip it.
The scipy. optimize package provides several commonly used optimization algorithms. A detailed listing is available: scipy. optimize (can also be found by help(scipy.
SciPy optimize provides functions for minimizing (or maximizing) objective functions, possibly subject to constraints. It includes solvers for nonlinear problems (with support for both local and global optimization algorithms), linear programing, constrained and nonlinear least-squares, root finding, and curve fitting.
If I understand your question correctly, I think this is what you're after:
from scipy.optimize import minimize
import numpy as np
def f(coord,x,y,r):
return np.sum( ((coord[0] - x)**2) + ((coord[1] - y)**2) - (r**2) )
x = np.array([0, 2, 0])
y = np.array([0, 0, 2])
r = np.array([.88, 1, .75])
# initial (bad) guess at (x,y) values
initial_guess = np.array([100,100])
res = minimize(f,initial_guess,args = [x,y,r])
Which yields:
>>> print res.x
[ 0.66666666 0.66666666]
You might also try the least squares method which expects an objective function that returns a vector. It wants to minimize the sum of the squares of this vector. Using least squares, your objective function would look like this:
def f2(coord,args):
x,y,r = args
# notice that we're returning a vector of dimension 3
return ((coord[0]-x)**2) + ((coord[1] - y)**2) - (r**2)
And you'd minimize it like so:
from scipy.optimize import leastsq
res = leastsq(f2,initial_guess,args = [x,y,r])
Which yields:
>>> print res[0]
>>> [ 0.77961518 0.85811473]
This is basically the same as using minimize
and re-writing the original objective function as:
def f(coord,x,y,r):
vec = ((coord[0]-x)**2) + ((coord[1] - y)**2) - (r**2)
# return the sum of the squares of the vector
return np.sum(vec**2)
This yields:
>>> print res.x
>>> [ 0.77958326 0.8580965 ]
Note that args
are handled a bit differently with leastsq
, and that the data structures returned by the two functions are also different. See the documentation for scipy.optimize.minimize
and scipy.optimize.leastsq
for more details.
See the scipy.optimize
documentation for more optimization options.
I noticed that the code in the accepted solution doesn't work any longer... I think maybe scipy.optimize
has changed its interface since the answer was posted. I could be wrong. Regardless, I second the suggestion to use the algorithms in scipy.optimize
, and the accepted answer does demonstrate how (or did at one time, if the interface has changed).
I'm adding an additional answer here, purely to suggest an alternative package that uses the scipy.optimize
algorithms at the core, but is much more robust for constrained optimization. The package is mystic
. One of the big improvements is that mystic
gives constrained global optimization.
First, here's your example, done very similarly to the scipy.optimize.minimize
way, but using a global optimizer.
from mystic import reduced
@reduced(lambda x,y: abs(x)+abs(y)) #choice changes answer
def objective(x, a, b, c):
x,y = x
eqns = (\
(x - a[0])**2 + (y - b[0])**2 - c[0]**2,
(x - a[1])**2 + (y - b[1])**2 - c[1]**2,
(x - a[2])**2 + (y - b[2])**2 - c[2]**2)
return eqns
bounds = [(None,None),(None,None)] #unnecessary
a = (0,2,0)
b = (0,0,2)
c = (.88,1,.75)
args = a,b,c
from mystic.solvers import diffev2
from mystic.monitors import VerboseMonitor
mon = VerboseMonitor(10)
result = diffev2(objective, args=args, x0=bounds, bounds=bounds, npop=40, \
ftol=1e-8, disp=False, full_output=True, itermon=mon)
print result[0]
print result[1]
With results looking like this:
Generation 0 has Chi-Squared: 38868.949133
Generation 10 has Chi-Squared: 2777.470642
Generation 20 has Chi-Squared: 12.808055
Generation 30 has Chi-Squared: 3.764840
Generation 40 has Chi-Squared: 2.996441
Generation 50 has Chi-Squared: 2.996441
Generation 60 has Chi-Squared: 2.996440
Generation 70 has Chi-Squared: 2.996433
Generation 80 has Chi-Squared: 2.996433
Generation 90 has Chi-Squared: 2.996433
STOP("VTRChangeOverGeneration with {'gtol': 1e-06, 'target': 0.0, 'generations': 30, 'ftol': 1e-08}")
[ 0.66667151 0.66666422]
2.99643333334
As noted, the choice of the lambda
in reduced
affects which point the optimizer finds as there is no actual solution to the equations.
mystic
also provides the ability to convert symbolic equations to a function, where the resulting function can be used as an objective, or as a penalty function. Here is the same problem, but using the equations as a penalty instead of the objective.
def objective(x):
return 0.0
equations = """
(x0 - 0)**2 + (x1 - 0)**2 - .88**2 == 0
(x0 - 2)**2 + (x1 - 0)**2 - 1**2 == 0
(x0 - 0)**2 + (x1 - 2)**2 - .75**2 == 0
"""
bounds = [(None,None),(None,None)] #unnecessary
from mystic.symbolic import generate_penalty, generate_conditions
from mystic.solvers import diffev2
pf = generate_penalty(generate_conditions(equations), k=1e12)
result = diffev2(objective, x0=bounds, bounds=bounds, penalty=pf, \
npop=40, gtol=50, disp=False, full_output=True)
print result[0]
print result[1]
With results:
[ 0.77958328 0.8580965 ]
3.6473132399e+12
The results are different than before because the penalty applied is different than we applied earlier in reduced
. In mystic
, you can select what penalty you want to apply.
The point was made that the equation has no solution. You can see from the result above, that the result is heavily penalized, so that's a good indication that there is no solution. However, mystic
has another way you can see there in no solution. Instead of applying a more traditional penalty
, which penalizes the solution where the constraints are violated... mystic
provides a constraint
, which is essentially a kernel transformation, that removes all potential solutions that don't meet the constants.
def objective(x):
return 0.0
equations = """
(x0 - 0)**2 + (x1 - 0)**2 - .88**2 == 0
(x0 - 2)**2 + (x1 - 0)**2 - 1**2 == 0
(x0 - 0)**2 + (x1 - 2)**2 - .75**2 == 0
"""
bounds = [(None,None),(None,None)] #unnecessary
from mystic.symbolic import generate_constraint, generate_solvers, simplify
from mystic.symbolic import generate_penalty, generate_conditions
from mystic.solvers import diffev2
cf = generate_constraint(generate_solvers(simplify(equations)))
result = diffev2(objective, x0=bounds, bounds=bounds, \
constraints=cf, \
npop=40, gtol=50, disp=False, full_output=True)
print result[0]
print result[1]
With results:
[ nan 657.17740835]
0.0
Where the nan
essentially indicates there is no valid solution.
FYI, I'm the author, so I have some bias. However, mystic
has been around almost as long as scipy.optimize
, is mature, and has had a more stable interface over that length of time. The point being, if you need a much more flexible and powerful constrained nonlinear optimizer, I suggest mystic
.
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