How to pass sys.argv[n] into a function in Python

Question

I am trying to pass "sys.argv[1]" into a function.

#!/usr/bin/env/ python
import sys
def main():
    test(sys.argv[1])
def test(sys.argv[1]):
    print "Hello " + sys.argv[1]

./arg.py World

File "./arg.py", line 5
def test(sys.argv[1]):
            ^
SyntaxError: invalid syntax

Not sure where to go from here after scowering the Interwebs for a few hours. I have also tried to set the "sys.argv[1]" to a variable and tried passing that into the function and still no avail.

Answer 1

I think you misunderstand the declaration and call of a function. In your program,there is only declaration,missing the calling statement. As for passing parameters from command line,here is an example which I prefer:

import sys
def hello(v):
    print 'hello '+v

def main(args):
    hello(args[1])

if __name__ == '__main__':
    main(sys.argv)

The program start to execute from the line 'if name == 'main' by calling the function defined previously and passing the sys.argv as parameter