I've been using Powershell-1.0 for command line needs for a while, instead of cmd.exe. Unfortunately, there are still some caveats when using Java. I need to pass a property to a jar, like that:
java -jar -Duser.language=en any.jar
This line works fine in cmd.exe, but not in Powershell as it searches for another jar:
Unable to access jarfile user.language=en
Using quotes doesn't help.
Is it doable in Powershell-1.0, or do I miss something in Java?
Take a look at my answer to this question. Note how you can use echoargs.exe to diagnose these sort of problems. Most likely the fix would be to quote the parameter e.g.:
java -jar "-Duser.language=en" any.jar
You can test that using echoargs (from PowerShell Community Extensions):
echoargs -jar "-Duser.language=en" any.jar
Arg 0 is <-jar>
Arg 1 is <-Duser.language=en>
Arg 2 is <any.jar>
Using quotes works fine for me in PowerShell on Windows 7.
java "-Dmy.property=value" -jar myjar.jar
Be careful: the jar name must be placed right after -jar
, and arguments placed after -jar myjar.jar
will be passed to the program inside the jarFile.
Try launching instead using the following pattern:
java -Duser.language=en -jar any.jar
That assumes that user.language is meant as a system property. If you meant it as a command line argument, change that to:
java -jar any.jar -Duser.language=en
I am actually surprised that the command line you mentioned works at all outside of powershell (though I have confirmed that it works fine for me too, even on Linux) and it is also a little strange that things would work differently inside and outside of powershell.
From java -help
:
Usage: java [-options] class [args...]
(to execute a class)
or java [-options] -jar jarfile [args...]
(to execute a jar file)
where options include:
...
-D<name>=<value>
set a system property
...
So basically you should always put the JAR filename directly after the -jar
command line option, and any JVM options (such as setting system properties with -D
) before.
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