PowerShell Boolean operators are $true and $false which mentions if any condition, action or expression output is true or false and that time $true and $false output returns as respectively, and sometimes Boolean operators are also treated as the 1 means True and 0 means false.
toString(boolean b): This method works same as String. valueOf() method. It belongs to the Boolean class and converts the specified boolean to String. If the passes boolean value is true then the returned string would be having “true” value, similarly for false the returned string would be having “false” value.
PowerShell can implicitly treat any type as a Boolean. It is important to understand the rules that PowerShell uses to convert other types to Boolean values.
A more clear usage might be to use switch parameters instead. Then, just the existence of the Unify parameter would mean it was set.
Like so:
param (
[int] $Turn,
[switch] $Unify
)
It appears that powershell.exe does not fully evaluate script arguments when the -File
parameter is used. In particular, the $false
argument is being treated as a string value, in a similar way to the example below:
PS> function f( [bool]$b ) { $b }; f -b '$false'
f : Cannot process argument transformation on parameter 'b'. Cannot convert value
"System.String" to type "System.Boolean", parameters of this type only accept
booleans or numbers, use $true, $false, 1 or 0 instead.
At line:1 char:36
+ function f( [bool]$b ) { $b }; f -b <<<< '$false'
+ CategoryInfo : InvalidData: (:) [f], ParentContainsErrorRecordException
+ FullyQualifiedErrorId : ParameterArgumentTransformationError,f
Instead of using -File
you could try -Command
, which will evaluate the call as script:
CMD> powershell.exe -NoProfile -Command .\RunScript.ps1 -Turn 1 -Unify $false
Turn: 1
Unify: False
As David suggests, using a switch argument would also be more idiomatic, simplifying the call by removing the need to pass a boolean value explicitly:
CMD> powershell.exe -NoProfile -File .\RunScript.ps1 -Turn 1 -Unify
Turn: 1
Unify: True
Try setting the type of your parameter to [bool]
:
param
(
[int]$Turn = 0
[bool]$Unity = $false
)
switch ($Unity)
{
$true { "That was true."; break }
default { "Whatever it was, it wasn't true."; break }
}
This example defaults $Unity
to $false
if no input is provided.
Usage
.\RunScript.ps1 -Turn 1 -Unity $false
This is an older question, but there is actually an answer to this in the PowerShell documentation. I had the same problem, and for once RTFM actually solved it. Almost.
https://docs.microsoft.com/en-us/powershell/module/microsoft.powershell.core/about/about_powershell_exe
Documentation for the -File parameter states that "In rare cases, you might need to provide a Boolean value for a switch parameter. To provide a Boolean value for a switch parameter in the value of the File parameter, enclose the parameter name and value in curly braces, such as the following: -File .\Get-Script.ps1 {-All:$False}"
I had to write it like this:
PowerShell.Exe -File MyFile.ps1 {-SomeBoolParameter:False}
So no '$' before the true/false statement, and that worked for me, on PowerShell 4.0
I think, best way to use/set boolean value as parameter is to use in your PS script it like this:
Param(
[Parameter(Mandatory=$false)][ValidateSet("true", "false")][string]$deployApp="false"
)
$deployAppBool = $false
switch($deployPmCmParse.ToLower()) {
"true" { $deployAppBool = $true }
default { $deployAppBool = $false }
}
So now you can use it like this:
.\myApp.ps1 -deployAppBool True
.\myApp.ps1 -deployAppBool TRUE
.\myApp.ps1 -deployAppBool true
.\myApp.ps1 -deployAppBool "true"
.\myApp.ps1 -deployAppBool false
#and etc...
So in arguments from cmd you can pass boolean value as simple string :).
Running powershell scripts on linux from bash gives the same problem. Solved it almost the same as LarsWA's answer:
Working:
pwsh -f ./test.ps1 -bool:true
Not working:
pwsh -f ./test.ps1 -bool=1
pwsh -f ./test.ps1 -bool=true
pwsh -f ./test.ps1 -bool true
pwsh -f ./test.ps1 {-bool=true}
pwsh -f ./test.ps1 -bool=$true
pwsh -f ./test.ps1 -bool=\$true
pwsh -f ./test.ps1 -bool 1
pwsh -f ./test.ps1 -bool:1
To summarize and complement the existing answers, as of Windows PowerShell v5.1 / PowerShell Core 7.0.0-preview.4:
David Mohundro's answer rightfully points that instead of [bool]
parameters you should use [switch]
parameters in PowerShell, where the presence vs. absence of the switch name (-Unify
specified vs. not specified) implies its value, which makes the original problem go away.
However, on occasion you may still need to pass the switch value explicitly, particularly if you're constructing a command line programmatically:
In PowerShell Core, the original problem (described in Emperor XLII's answer) has been fixed.
That is, to pass $true
explicitly to a [switch]
parameter named -Unify
you can now write:
pwsh -File .\RunScript.ps1 -Unify:$true # !! ":" separates name and value, no space
The following values can be used: $false
, false
, $true
, true
, but note that passing 0
or 1
does not work.
Note how the switch name is separated from the value with :
and there must be no whitespace between the two.
Note: If you declare a [bool]
parameter instead of a [switch]
(which you generally shouldn't), you must use the same syntax; even though -Unify $false
should work, it currently doesn't - see this GitHub issue.
In Windows PowerShell, the original problem persists, and - given that Windows PowerShell is no longer actively developed - is unlikely to get fixed.
The workaround suggested in LarsWA's answer - even though it is based on the official help topic as of this writing - does not work in v5.1
Using -Command
instead of -File
is the only effective workaround:
:: # From cmd.exe
powershell -Command "& .\RunScript.ps1 -Unify:$true"
With -Command
you're effectively passing a piece of PowerShell code, which is then evaluated as usual - and inside PowerShell passing $true
and $false
works (but not true
and false
, as now also accepted with -File
).
Caveats:
Using -Command
can result in additional interpretation of your arguments, such as if they contain $
chars. (with -File
, arguments are literals).
Using -Command
can result in a different exit code.
For details, see this answer and this answer.
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