how to pass arguments to imported script in Python

Question

I have a script (script1.py) of the following form:

#!/bin/python

import sys

def main():
    print("number of command line options: {numberOfOptions}".format(numberOfOptions = len(sys.argv)))
    print("list object of all command line options: {listOfOptions}".format(listOfOptions = sys.argv))
    for i in range(0, len(sys.argv)):
        print("option {i}: {option}".format(i = i, option = sys.argv[i]))

if __name__ == '__main__':
    main()

I want to import this script in another script (script2.py) and pass to it some arguments. The script script2.py could look something like this:

import script1

listOfOptions = ['option1', 'option2']
#script1.main(listOfOptions) insert magic here

How could I pass the arguments defined in script2.py to the main function of script1.py as though they were command line options?

So, for example, would it be Pythonic to do something such as the following?:

import script1
import sys

sys.argv = ['option1', 'option2']
script1.main()

Answer 1

Separate command line parsing and called function

For reusability of your code, it is practical to keep the acting function separated from command line parsing

scrmodule.py

def fun(a, b):
    # possibly do something here
    return a + b

def main():
    #process command line argumens
    a = 1 #will be read from command line
    b = 2 #will be read from command line
    # call fun()
    res = fun(a, b)
    print "a", a
    print "b", b
    print "result is", res

if __name__ == "__main__":
    main()

Reusing it from another place

from scrmodule import fun

print "1 + 2 = ", fun(1, 2)