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I am trying to pass an array to the python
import sys
arr = sys.argv[1]
print(arr[2])
My command is
python3 test.py [1,2,3,4,5] 0
I hope the result it
2
However, it is
,
528
To create a deep copy of an array in Python, use the array. copy() method. The array. copy() method does not take any argument because it is called on the original array and returns the deep copied array.
But there's a simpler way: Just write the arguments separately, and use a slice of sys. argv as your list. Space-separated arguments is the standard way to pass multiple arguments to a commandline program (e.g., multiple filenames to less , rm , etc.). PS.
Give the list as user input using the list(),map(),split(),int functions and store it in a variable. Pass 'i', above given list as arguments to the array() function to create an array. Store it in another variable. Here 'i' indicates the datatype of the given array elements is integer.
The elements of argv are strings, they're not parsed like literals in the program.
You should just pass a comma-separated string (without the brackets):
python3 test.py 1,2,3,4,5 0
and then use split() to convert it to an array.
import sys
arr = sys.argv[1].split(',')
print(arr[2])
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