How to pass all arguments as collection to another function and not as single argument? [duplicate]

Question

I have a function that accepts any number and kind of arguments, so no specific parameter has been defined. This function should call another function passing all arguments.

The problem is that I can pass "arguments" in order to include all arguments but in this case it will work like a single argument and not the way we expect arguments to work.

An example:

The main function:

function handleCall() {    // let's call a sub-function    // and pass all arguments (my question is how this is handled the right way)    function callSubFunction( arguments ); }  function callSubfunction( userid, customerid, param) {    // passed arguments are now     alert( 'userid = ' + userid );     // this will not work, you have to use arguments[2]    alert( param );   }  The example call:  handleCall( 1029, 232, 'param01' ); 

Using the approach above, all arguments will be stored in "userid" as pseudo-array and items can be accessed e.g. arguments[2] but not using the parameter name "param".

In ColdFusion, the solution for such stuff is the parameter "argumentCollection", this way you can pass parameters stored in a structure without being converted to a single argument with the type struct containing all key/values.

How can I achieve the same with JavaScript?

Answer 1

If you want to do the same with the spread syntax, you can use the following:

function handleCall(...args) {     callSubFunction(...args); }