How to pass a 2D array by pointer in C?

Question

I am learning C and am having trouble passing the pointer of a 2D array to another function that then prints the 2D array. Any help would be appreciated.

int main( void ){     char array[50][50];     int SIZE;      ...call function to fill array... this part works.      printarray( array, SIZE ); }  void printarray( char **array, int SIZE ){     int i;     int j;      for( j = 0; j < SIZE; j++ ){         for( i = 0; i < SIZE; i ++){             printf( "%c ", array[j][i] );         }         printf( "\n" );     } } 

Answer 1

char ** doesn't represent a 2D array - it would be an array of pointers to pointers. You need to change the definition of printarray if you want to pass it a 2D array:

void printarray( char (*array)[50], int SIZE ) 

or equivalently:

void printarray( char array[][50], int SIZE )