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I am learning C and am having trouble passing the pointer of a 2D array to another function that then prints the 2D array. Any help would be appreciated.
int main( void ){ char array[50][50]; int SIZE; ...call function to fill array... this part works. printarray( array, SIZE ); } void printarray( char **array, int SIZE ){ int i; int j; for( j = 0; j < SIZE; j++ ){ for( i = 0; i < SIZE; i ++){ printf( "%c ", array[j][i] ); } printf( "\n" ); } } 
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// The following program works only if your compiler is C99 compatible. If compiler is not C99 compatible, then we can use one of the following methods to pass a variable sized 2D array. In this method, we must typecast the 2D array when passing to function.
Array can be passed to function in C using pointers and because they are passed by reference changes made on an array will also be reflected on the original array outside function scope.
A whole array cannot be passed as an argument to a function in C++. You can, however, pass a pointer to an array without an index by specifying the array's name.
char ** doesn't represent a 2D array - it would be an array of pointers to pointers. You need to change the definition of printarray if you want to pass it a 2D array:
void printarray( char (*array)[50], int SIZE ) or equivalently:
void printarray( char array[][50], int SIZE ) If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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