Let's suppose i have the following string
honeypot=&name=Zelalem+Mekonen&email=zola%40programmer.net&message=Hello+And+this+is+a+test+message...
and i want to convert it into url.Values
struct and i have the following
data := url.Values{}
parameters := strings.Split(request.Body, "&")
for _, parameter := range parameters {
parts := strings.Split(parameter, "=")
data.Add(parts[0], parts[1])
}
which does convert it into url.Values
but the problem is that it doesn't convert url encoded values like +
into space, so first is there a better way to parse this? then if not how do i convert url encoded string to normal string first?
Thank's For Your Help...o
URL Encoding or Escaping a String in Go Go provides the following two functions to encode or escape a string so that it can be safely placed inside a URL: QueryEscape(): Encode a string to be safely placed inside a URL query string. PathEscape(): Encode a string to be safely placed inside a URL path segment.
Go has good support for url parsing. URL contains a scheme, authentication info, host, port, path, query params, and query fragment. we can parse URL and deduce what are the parameter is coming to the server and then process the request accordingly.
URL Parsing. The URL parsing functions focus on splitting a URL string into its components, or on combining URL components into a URL string.
You could use url.ParseQuery
to convert the raw query to url.Values
with unescaping
package main
import (
"fmt"
"net/url"
)
func main() {
t := "honeypot=&name=Zelalem+Mekonen&email=zola%40programmer.net&message=Hello+And+this+is+a+test+message..."
v, err := url.ParseQuery(t)
if err != nil {
panic(err)
}
fmt.Println(v)
}
Result:
map[honeypot:[] name:[Zelalem Mekonen] email:[[email protected]] message:[Hello And this is a test message...]]
You could first decode the URL with net/url/QueryUnescape
.
It does converts '+
' into '' (space).
Then you can start splitting the decoded string, or use net/url/#ParseRequestURI
and get the URL.Query
.
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