In react-router v3 I could access it with props.location.query.foo
(if the current location was ?foo=bar
)
In [email protected]
props.location
only has props.location.search
with is a string like ?foo=bar&other=thing
.
Perhaps I need to manually parse and deconstruct that string to find the value for foo
or other
.
Screenshot of console.log(this.props)
: (Note how from ?artist=band
here I'd like to get the value from artist
which is the value band
)
Get a single Query String value location.search object: import React from 'react'; import { useSearchParams } from 'react-router-dom'; const Users = () => { const [searchParams] = useSearchParams(); console. log(searchParams); // ▶ URLSearchParams {} return <div>Users</div>; };
To pass in query parameters, we just add them to the Link s to props as usual. For example, we can write the following: We first defined the useQuery Hook to get the query parameters of the URL via the URLSearchParams constructor. We get the useLocation() s search property.
Looks like you already assumed correct. The ability to parse query strings was taken out of V4 because there have been requests over the years to support different implementation. With that, the team decided it would be best for users to decide what that implementation looks like. We recommend importing a query string lib. The one you mentioned has worked great for me so far.
const queryString = require('query-string'); const parsed = queryString.parse(props.location.search);
You can also use new URLSearchParams
if you want something native and it works for your needs
const search = props.location.search; // could be '?foo=bar' const params = new URLSearchParams(search); const foo = params.get('foo'); // bar
You can read more about the decision here
I proffer my little ES6
shape function, awesome, light weight and useful:
getQueryStringParams = query => { return query ? (/^[?#]/.test(query) ? query.slice(1) : query) .split('&') .reduce((params, param) => { let [key, value] = param.split('='); params[key] = value ? decodeURIComponent(value.replace(/\+/g, ' ')) : ''; return params; }, {} ) : {} };
Every thing is here, hope to help you.
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