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string binary = Convert.ToString(15, 2);
Console.WriteLine("{0}", binary);
Prints:
1111
I want it to print 00001000
Because the data type is of string and not integer I cannot do something like this:
Console.WriteLine("{0:00000000}", binary);
520
To pad a numeric value with a specific number of leading zeros. Create a custom format string that uses the zero placeholder ("0") for each of the leading zeros to appear in the string, and that uses either the zero placeholder or the digit placeholder ("#") to represent each digit in the default string.
To pad a numeric value with leading zeros to a specific length Determine how many digits to the left of the decimal you want the string representation of the number to have. Include any leading zeros in this total number of digits. Define a custom numeric format string that uses the zero placeholder "0" to represent the minimum number of zeros.
And, finally, since Java 5, we can use String.format (): We should note that by default the padding operation will be performed using spaces. That's the reason why we need to use the replace () method if we want to pad with zeros or any other character.
To pad an integer with leading zeros to a specific length. To display the integer as a hexadecimal value, call its ToString (String) method and pass the string "X n " as the value of the format parameter, where n represents the minimum length of the string.
Console.WriteLine( binary.PadLeft(8, '0'));
You can try this one:
Convert.ToString(15, 2).PadLeft(8, '0');
It should give you 00001111
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