How to open in default browser in C#

Question

You can just write

System.Diagnostics.Process.Start("http://google.com");

EDIT: The WebBrowser control is an embedded copy of IE.
Therefore, any links inside of it will open in IE.

To change this behavior, you can handle the Navigating event.

For those finding this question in dotnet core. I found a solution here

Code:

private void OpenUrl(string url)
{
    try
    {
        Process.Start(url);
    }
    catch
    {
        // hack because of this: https://github.com/dotnet/corefx/issues/10361
        if (RuntimeInformation.IsOSPlatform(OSPlatform.Windows))
        {
            url = url.Replace("&", "^&");
            Process.Start(new ProcessStartInfo("cmd", $"/c start {url}") { CreateNoWindow = true });
        }
        else if (RuntimeInformation.IsOSPlatform(OSPlatform.Linux))
        {
            Process.Start("xdg-open", url);
        }
        else if (RuntimeInformation.IsOSPlatform(OSPlatform.OSX))
        {
            Process.Start("open", url);
        }
        else
        {
            throw;
        }
    }
}

public static void GoToSite(string url)
{
     System.Diagnostics.Process.Start(url);
}

that should solve your problem

After researching a lot I feel most of the given answer will not work with dotnet core. 1.System.Diagnostics.Process.Start("http://google.com"); -- Will not work with dotnet core

2.It will work but it will block the new window opening in case default browser is chrome

 myProcess.StartInfo.UseShellExecute = true; 
    myProcess.StartInfo.FileName = "http://some.domain.tld/bla";
    myProcess.Start();

Below is the simplest and will work in all the scenarios.

Process.Start("explorer", url);

Did you try Processas mentioned here: http://msdn.microsoft.com/de-de/library/system.diagnostics.process.aspx?

You could use

Process myProcess = new Process();

try
{
    // true is the default, but it is important not to set it to false
    myProcess.StartInfo.UseShellExecute = true; 
    myProcess.StartInfo.FileName = "http://some.domain.tld/bla";
    myProcess.Start();
}
catch (Exception e)
{
    Console.WriteLine(e.Message);
}