I have a method of a mocked object that can be called multiple times (think recursion). The method is defined like this:
public void doCommit() { }
In order to tell it to fail I use this convention:
doThrow(new RuntimeException()).when(mMockedObject).doCommit();
This though, makes the method throw this exception EVERY time it is called. How can I make it so that it only, for example, throws it the first and third time it is called? Which means that, for example, the second and forth time it just returns without throwing an exception. Please note that I am not the author of doCommit(), nor do I have source code that I can change.
Mockito + Catch-Exception + AssertJ.
Mockito provides following methods that can be used to mock void methods. doAnswer() : We can use this to perform some operations when a mocked object method is called that is returning void. doThrow() : We can use doThrow() when we want to stub a void method that throws exception.
If a method return type is a custom class, a mock returns null because there is no empty value for a custom class. RETURN_MOCKS will try to return mocks if possible instead of null . Since final class cannot be mocked, null is still returned in that case.
I figured it out (with some hints from Igor). This is how you stub consecutive void method calls:
doThrow(new RuntimeException()).doNothing().doThrow(...).doNothing().when(mMockedObject).doCommit();
thanks Igor!
Reading Stubbing Consecutive Calls doco, something like this might do it:
when(mMockedObject.doCommit()) .thenThrow(new RuntimeException()) .thenCallRealMethod() .thenThrow(new RuntimeException()) .thenCallRealMethod();
If you don't want to actually call the underlying method then you should use thenAnswer
instead of thenCallRealMethod
method and provide an empty stub imlementation.
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