How to Omit multiple properties in a succint way using Omit<>

Question

In the following type definition I am using Omit two time to remove two property from B definition. I would like to know if it is possible to use only a single Omit but removing two or more properties in one shot.

export type A = Readonly<{
  x: number;
  y: number;
  j: string;
  k: string;
}>;

export type B = Omit<A, 'j'> & Omit<A, 'k'>

Answer 1

You just need to use a union as the second type parameter to remove all constituents in the union from the first type parameter:

export type A = Readonly<{
  x: number;
  y: number;
  j: string;
  k: string;
}>;

export type B = Omit<A, 'j' | 'k'>
// Same as
// type B = {
//     readonly x: number;
//     readonly y: number;
// }

play