How to notify myself when a python script runs into an error or just stops?

Question

I have a python script which runs on Ubuntu and processes the content of a MySQL Database. I want to be informed when the script runs into an unhandled exception or when it is done processing.

What is the appropriate way to make this happen?

I thought of sending myself an email from within python using the method shown in this SO-Answer, but to be able to do that I have to hardcode my logindata - which I am not comfortable with (the script runs on a public server within the company).

Any suggestions to bypass that or to make it happen using a more appropriate way?

Answer 1

This worked as charm: https://www.quora.com/How-can-I-send-a-push-notification-to-my-Android-phone-with-a-Python-script

ON PC: install notify-me

pip install notify-run

then register it as: notify-run register

now on your mobile scan the code and allow notification from this site.

Then your script can notify you like this:

from notify_run import Notify
notify = Notify()
notify.send('any message you want')

Answer 2

You typically don't need to supply login data when sending an email over SMTP. If I were you, I'd experiment with the code given in the answer you've linked to and try it out with your company's SMTP server.