I'm new in React Native and trying create my first app. So I have a question:
I got 2 screens (using react-navigation). At first screen there is a render of app logo with spinner(from native-base) and fetch to the server at the same time. And I need to navigate to another screen only when fetch is over and responce is handled. All I found at react-navigation docs is a solution with button, but it's not my case. Also I don't want to use ActivityIndicatorIOS (app should be correct for Android).
Please help me understand what should I do?
Thanks a lot!
Just call the navigate function in then callback of the fetch or handle error appropriately in catch.
Every screen in react-navigation gets the navigation prop. You can use the navigate function to navigate to any screen. Something like this
class FirstScreen extends React.Component {
static navigationOptions = {
title: 'First',
}
componentDidMount(){
const {navigate} = this.props.navigation;
navigate('Second');
fetch('http://apiserver').then( (response) => {
navigate('Second');
});
}
render() {
return (
<AppLogo />
);
}
}
const AppNavigator = StackNavigator({
First: {
screen: FirstScreen,
},
Second: {
screen: SecondScreen,
},
});
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