I have an 8x8 matrix, like this:
char matrix[8][8];
Also, I have an array of 64 elements, like this:
char array[64];
Then I have drawn the matrix as a table, and filled the cells with numbers, each number being incremented from left to right, top to bottom.
If I have, say, indexes 3 (column) and 4 (row) into the matrix, I know that it corresponds to the element at position 35 in the array, as it can be seen in the table that I've drawn. I believe there is some sort of formula to translate the 2 indexes of the matrix into a single index of the array, but I can't figure out what it is.
Any ideas?
Functions Used data-is the input vector which becomes the data elements of the matrix. nrow-is the numbers of rows to be created. ncol-is the numbers of columns to be created. byrow-is a logical clue,if it is true then input vector elements are arranged by row.
In one-dimensional arrays in C, indexing starts from 0 and ends at size-1, and if we try to access an element out of range, it will return garbage value. We must include a data type, variable name for array, and array size in square brackets while declaring one-dimensional arrays in C.
It can also be seen as a collection of 1D arrays. It is also known as the Matrix. Its dimension can be increased from 2 to 3 and 4 so on. They all are referred to as a multi-dimension array.
Rules for Declaring One Dimensional Array If the size is declared as 10, programmers can store 10 elements. An array index always starts from 0. For example, if an array variable is declared as s[10], then it ranges from 0 to 9. Each array element is stored in a separate memory location.
The way most languages store multi-dimensional arrays is by doing a conversion like the following:
If matrix
has size, n (rows) by m (columns), and we're using "row-major ordering" (where we count along the rows first) then:
matrix[ i ][ j ] = array[ i*m + j ]
.
Here i goes from 0 to (n-1) and j from 0 to (m-1).
So it's just like a number system of base 'm'. Note that the size of the last dimension (here the number of rows) doesn't matter.
For a conceptual understanding, think of a (3x5) matrix with 'i' as the row number, and 'j' as the column number. If you start numbering from i,j = (0,0) --> 0
. For 'row-major' ordering (like this), the layout looks like:
|-------- 5 ---------|
Row ______________________ _ _
0 |0 1 2 3 4 | |
1 |5 6 7 8 9 | 3
2 |10 11 12 13 14| _|_
|______________________|
Column 0 1 2 3 4
As you move along the row (i.e. increase the column number), you just start counting up, so the Array indices are 0,1,2...
. When you get to the second row, you already have 5
entries, so you start with indices 1*5 + 0,1,2...
. On the third row, you have 2*5
entries already, thus the indices are 2*5 + 0,1,2...
.
For higher dimension, this idea generalizes, i.e. for a 3D matrix
L by N by M:
matrix[ i ][ j ][ k ] = array[ i*(N*M) + j*M + k ]
and so on.
For a really good explanation, see: http://www.cplusplus.com/doc/tutorial/arrays/; or for some more technical aspects: http://en.wikipedia.org/wiki/Row-major_order
For row-major ordering, I believe the statement matrix[ i ][ j ] = array[ i*n + j ]
is wrong.
The offset should be offset = (row * NUMCOLS) + column
.
Your statement results to be row * NUMROWS + column
, which is wrong.
The links you provided give a correct explanation.
Something like this?
//columns = amount of columns, x = column, y = row
var calculateIndex = function(columns, x, y){
return y * columns + x;
};
The example below converts an index back to x and y coordinates.
//i = index, x = amount of columns, y = amount of rows
var calculateCoordinates = function(index, columns, rows){
//for each row
for(var i=0; i<rows; i++){
//check if the index parameter is in the row
if(index < (columns * i) + columns && index >= columns * i){
//return x, y
return [index - columns * i, i];
}
}
return null;
};
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