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hi ı am triying to take the data of files in a folder with system function this is the code
char path[100],command[120];
scanf("%s",&path);
sprintf(command,"echo $(ls %s) > something.txt",path);
system(command);
but when I look to the something.txt there is no new line. This is the output, all on one line with many file names omitted:
acpi adjtime adobe apparmor.d arch-release asound.conf ati at-spi2 avahi bash.bash_logout ... wpa_supplicant X11 xdg xinetd.d xml yaourtrc
I did try -e -E -n options of echo but it didn't work. How to make a new line after each of these files?
698
The best way to remove the new line is to add '-n'. This signals not to add a new line. When you want to write more complicated commands or sort everything in a single line, you should use the '-n' option.
For example, you can use the echo command to append the text to the end of the file as shown. Alternatively, you can use the printf command (do not forget to use \n character to add the next line). You can also use the cat command to concatenate text from one or more files and append it to another file.
You shouldn't use echo. Do just
sprintf(command,"ls %s > something.txt",path);
system(command);
When you use echo it outputs all command line arguments to the stdout, one by one, separated by the space character. Newline character (which is output of ls command) works as an argument separator, just as space.
106
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