How to make `make` make an a executable for each C file in a folder?

Question

My question is deceptively simple, but I have lost several hours of study trying to get the solution. I'm trying to create a Makefile that builds an executable for each .c file in a directory.

I have tried the following:

CC = gcc
SRCS = $(wildcard *.c)
OBJS = $(patsubst %.c,%.o,$(SRCS))

all: $(OBJS)
$(CC) $< -o $@

%.o: %.c
    $(CC) $(CPFLAGS)  -c  $<

but this way it is creating only .o files, and not any executables. I need a rule that makes an executable for each of these .o files. Something like the following:

gcc src.o -o src

Answer 1

rob's answer doesn't seem to work on my machine. Perhaps, as the complete Makefile:

SRCS = $(wildcard *.c)

all: $(SRCS:.c=)

.c:
     gcc $(CPFLAGS) $< -o $@

(The last two lines, are on my machine, unnecessary, as the default rules are adequate.)

Answer 2

Your all is telling it just to build the object files. Add something like

EXEC = $(patsubst %.c,%,$(SRCS))

all: $(EXEC)