How to make git log output that just shows date and hash on one line?

Question

I need to get the Date and commit results of a set of github in this format:

Date Commit
19 Mar 2015 b6959eafe0df6031485509c539e22eaf2780919c
1 Apr 2015 9a1f13339cc7d43930440c2350ea3060b72c8503
1 Apr 2015 1e76036421ca4d72c371182fc494af514911b099

I am able to get the date with this command:

git log | grep Date: | awk '{print  $4 " " $3 " " $6}'

and the commit with

git log | grep commit | awk '{print $2}'

How can I combine the commands, so as to print both results in the same line?

Here is an example of the git log:

commit 1e76036421ca4d72c371182fc494af514911b099
Author: xxxx
Date:   Wed Apr 1 17:35:36 2015 +0200

    First web app commit

    First web app commit

commit 9a1f13339cc7d43930440c2350ea3060b72c8503
Author: xxxx
Date:   Wed Apr 1 17:28:42 2015 +0200

   change from app to website

commit b6959eafe0df6031485509c539e22eaf2780919c
Author: xxx
Date:   Thu Mar 19 18:58:33 2015 +0100

   First remote commit: hello world

    scheleton of the project now available

commit a41d419de46a59e72dbc52e5f39c9d8a8a9af72a
Author: xxxx
Date:   Thu Mar 19 17:31:16 2015 +0100

    Initial commit

Answer 1

The "git log" command is powerful enough to handle this on its own. Play around with variations on this:

git log --date=iso --pretty=format:"date={%ad}, commit={%H}"

For me this outputs:

date={2014-12-12 14:14:23 -0800}, commit={75390af8bcd42c4dde6d841dc53f66a9ca91f460}
date={2014-12-09 18:53:32 -0800}, commit={8dcf9eb10611e6ac778e518cf37efb041c69f5b5}
date={2014-12-11 17:17:26 -0800}, commit={c3c1120b6dda6b317e1de5c7fe4eed7c8741ea1a}

To achieve the exact format you specified (though with the date formatted a bit more reasonably), try this:

 ​git log --date=short --pretty=format:"%ad %H"

Which outputs things like:

2015-08-18 1d0ca5a596f02958c4ba8ff269def3f235c64495
2015-08-18 d92fc3ebb62d2ca3e24322db2b669fdaebde7ea1
2015-08-18 6ba3970620e19699c2969b1eed5c479b07b8908a