Starting with this data frame
myDF = structure(list(Value = c(-2, -1, 0, 1, 2)), .Names = "Value", row.names = c(NA, 5L), class = "data.frame")
Suppose I want to run this function on every row of myDF$Value
getNumberInfo <- function(x) {
if(x %% 2 ==0) evenness = "Even" else evenness="Odd"
if(x > 0) positivity = "Positive" else positivity = "NonPositive"
if (positivity == "Positive") logX = log(x) else logX=NA
c(evenness,positivity,logX)
}
... to get this data frame
structure(list(Value = c(-2, -1, 0, 1, 2), Evenness = c("Even",
"Odd", "Even", "Odd", "Even"), Positivity = c("NonPositive",
"NonPositive", "NonPositive", "Positive", "Positive"), Log = c(NA,
NA, NA, "0", "0.693147180559945")), row.names = c(NA, 5L), .Names = c("Value",
"Evenness", "Positivity", "Log"), class = "data.frame")
How do I concatenate two columns in R? To concatenate two columns you can use the <code>paste()</code> function. For example, if you want to combine the two columns A and B in the dataframe df you can use the following code: <code>df['AB'] <- paste(df$A, df$B)</code>.
You can add new columns to a dataframe using the $ and assignment <- operators. To do this, just use the df$name notation and assign a new vector of data to it.
1 Answer. In R programming, functions do not return multiple values, however, you can create a list that contains multiple objects that you want a function to return.
You might want to change your getNumberInfo
function to return a list rather than a vector, so that the values can have different types. As it is, they're all being cast to strings, which probably isn't what you want for logX
.
getNumberInfo <- function(x) {
if(x %% 2 ==0) evenness = "Even" else evenness="Odd"
if(x > 0) positivity = "Positive" else positivity = "NonPositive"
if (positivity == "Positive") logX = log(x) else logX=NA
list(evenness,positivity,logX)
}
Furthermore, you can use the names to a somewhat better effect so that you don't have to repeat them:
getNumberInfo <- function(x) {
list(evenness = if(x %% 2 ==0) "Even" else "Odd",
positivity = if(x > 0) "Positive" else "NonPositive",
logX = if(x > 0) log(x) else NA)
}
Then the solution becomes simple:
> cbind(myDF, t(sapply(myDF$Value, getNumberInfo)))
Value evenness positivity logX
1 -2 Even NonPositive NA
2 -1 Odd NonPositive NA
3 0 Even NonPositive NA
4 1 Odd Positive 0
5 2 Even Positive 0.6931472
Finally, if you use ifelse
(which can work on vectors) instead of if
, it gets even simpler because you don't have to call apply
:
getNumberInfo <- function(x) {
list(evenness = ifelse(x %% 2 ==0, "Even", "Odd"),
positivity = ifelse(x > 0, "Positive", "NonPositive"),
logX = ifelse(x > 0, log(x), NA))
}
> cbind(myDF, getNumberInfo(myDF$Value))
Value evenness positivity logX
1 -2 Even NonPositive NA
2 -1 Odd NonPositive NA
3 0 Even NonPositive NA
4 1 Odd Positive 0.0000000
5 2 Even Positive 0.6931472
That last solution emits a warning, because it's actually computing the log of every element, not just those with x>0
. Not sure the most elegant way to deal with that.
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