How to make a list as the default value for a dictionary? [duplicate]

Question

I have a Python code that looks like:

if key in dict:   dict[key].append(some_value) else:   dict[key] = [some_value] 

but I figure there should be some method to get around this 'if' statement. I tried:

dict.setdefault(key, []) dict[key].append(some_value) 

and

dict[key] = dict.get(key, []).append(some_value) 

but both complain about "TypeError: unhashable type: 'list'". Any recommendations?

Answer 1

The best method is to use collections.defaultdict with a list default:

from collections import defaultdict dct = defaultdict(list) 

Then just use:

dct[key].append(some_value) 

and the dictionary will create a new list for you if the key is not yet in the mapping. collections.defaultdict is a subclass of dict and otherwise behaves just like a normal dict object.

When using a standard dict, dict.setdefault() correctly sets dct[key] for you to the default, so that version should have worked just fine. You can chain that call with .append():

>>> dct = {} >>> dct.setdefault('foo', []).append('bar')  # returns None! >>> dct {'foo': ['bar']} 

However, by using dct[key] = dct.get(...).append() you replace the value for dct[key] with the output of .append(), which is None.