How to make a custom class be able to be received by range()?

Question

range() in Python seems to accept integer as parameter only. How to make range() accept a custom class as parameter?

I've defined a class such as:

class MyInteger:
    def __init__(self, a:int):
        self._a = a
    def __int__(self):
        return self._a

And I tried:

n = MyInteger(5)
for i in range(n):
    print(i)

It always causes 'object cannot be interpreted as an integer' whether or not I defined __int__. Is there any way to solve this problem?

range(n) cannot be changed to range(int(n)) or range(n.get_int()).

Answer 1

Implement __index__ to allow your class instances to be interpreted as an int

class MyInteger:

    def __init__(self, a:int):
        self._a = a

    def __index__(self):
        return self._a

n = MyInteger(5)
for i in range(n):
    print(i)