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$('#demo').html('<img src="/parcel-pricer/img/ajax-loader.gif" style="margin-left:50px;width:20%;margin-bottom:10px;">');
$('#demo').show();
$('#demo').load('fast.php?send='+send+'&delv='+delv+'&quant='+quant+'&weight='+weight+'&length='+length+'&width='+width+'&height='+height+'&send1='+send1+'&delv1='+delv1+'&value='+value+'&country_send='+country_send+'&country_delv='+country_delv);
$('#demo1').html('<img src="/parcel-pricer/img/ajax-loader.gif" style="margin-left:50px;width:20%;margin-bottom:10px;">');
$('#demo1').show();
$('#demo1').load('Timed.php?send='+send+'&delv='+delv+'&quant='+quant+'&weight='+weight+'&length='+length+'&width='+width+'&height='+height+'&send1='+send1+'&delv1='+delv1+'&value='+value+'&country_send='+country_send+'&country_delv='+country_delv);
i am load multiple php file using .load() function. all file are load for some time but php file not load for one time his load for by one by one.. so plz how is ???
276
It is possible to insert the content of one PHP file into another PHP file (before the server executes it), with the include or require statement. The include and require statements are identical, except upon failure: require will produce a fatal error (E_COMPILE_ERROR) and stop the script.
Pragmatically speaking, this is the typical order: PHP runs first and constructs the page. The browser loads the resulting HTML (any JavaScript found gets executed immediately)
- There are two ways to combine PHP with JavaScript to achieve a dynamic and personalized result: 1) By writing the entire JS script within PHP code and adding it to the web page with PHP function ' echo ' (or ' print ').
Try using the callbacks like:
// load to first target div
$( "#target_1" ).load( "url_1", function() {
// load to second target div
$( "#target_2" ).load( "url_2", function() {
// ... and so on if any
});
});
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