I am using this code for storing the image into isolate storage at the time of camera action completed.
void camera_Completed(object sender, PhotoResult e)
{
BitmapImage objImage = new BitmapImage();
//objImage.SetSource(e.ChosenPhoto);
//Own_Image.Source = objImage;
using (var isolatedStorage = IsolatedStorageFile.GetUserStoreForApplication())
{
fnam = e.OriginalFileName.Substring(93);
MessageBox.Show(fnam);
if (isolatedStorage.FileExists(fnam))
isolatedStorage.DeleteFile(fnam);
IsolatedStorageFileStream fileStream = isolatedStorage.CreateFile(fnam);
BitmapImage bitmap = new BitmapImage();
bitmap.SetSource(e.ChosenPhoto);
WriteableBitmap wb = new WriteableBitmap(bitmap);
wb.SaveJpeg(fileStream, wb.PixelWidth, wb.PixelHeight, 100, 100);
MessageBox.Show("File Created");
fileStream.Close();
}
}
Now I want to take the image from isolated storage and display it in my image control.
Is it possible?
Yes it is. You can use this function to load image from IsolatedStorage:
private static BitmapImage GetImageFromIsolatedStorage(string imageName)
{
var bimg = new BitmapImage();
using (var iso = IsolatedStorageFile.GetUserStoreForApplication())
{
using (var stream = iso.OpenFile(imageName, FileMode.Open, FileAccess.Read))
{
bimg.SetSource(stream);
}
}
return bimg;
}
Usage:
ImageControl.Source = GetImageFromIsolatedStorage(fnam);
Something like this:
public BitmapImage LoadImageFromIsolatedStorage(string path) {
var isf = IsolatedStorageFile.GetUserStoreForApplication();
using (var fs = isf.OpenFile(path, System.IO.FileMode.Open)) {
var image = new BitmapImage();
image.SetSource(fs);
return image;
}
}
In your code
image1.Source = LoadImageFromIsolatedStorage("image.jpg");
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