How to list all fields of a class (and no methods)?

Question

Suppose o is a Python object, and I want all of the fields of o, without any methods or __stuff__. How can this be done?

I've tried things like:

[f for f in dir(o) if not callable(f)]  [f for f in dir(o) if not inspect.ismethod(f)] 

but these return the same as dir(o), presumably because dir gives a list of strings. Also, things like __class__ would be returned here, even if I get this to work.

Answer 1

You can get it via the __dict__ attribute, or the built-in vars function, which is just a shortcut:

>>> class A(object): ...     foobar = 42 ...     def __init__(self): ...         self.foo = 'baz' ...         self.bar = 3 ...     def method(self, arg): ...         return True ... >>> a = A() >>> a.__dict__ {'foo': 'baz', 'bar': 3} >>> vars(a) {'foo': 'baz', 'bar': 3} 

There's only attributes of the object. Methods and class attributes aren't present.