How to keep baseUrl when using uri() in spring webflux

Question

Using spring boot 2.1.3.RELEASE, WebClient will stop using the provided baseUrl when passing an URI to uri() method. It will keep baseUrl when a string is passed to uri() though.

How can I provide a baseUrl and pass an URI?

public WebClient webClient() {
  return WebClient.builder()
    .baseUrl("https://example.com/")
    .build();
}

and

webClient.get().uri(URI.create("/foo/%23bar"))... 

throws

java.lang.IllegalArgumentException: URI is not absolute:

and the request url becomes

request url: /foo/%23bar

Answer 1

If you pass new URI Object, you override base URI. You should use uri method with lambda as a parameter, like in example:

final WebClient webClient = WebClient
  .builder()
  .baseUrl("http://localhost")
  .build();
webClient
  .get()
  .uri(uriBuilder -> uriBuilder.pathSegment("api", "v2", "json", "test").build())
  .exchange();

Answer 2

A slightly different way - use path instead of pathSegment on existing uri object. It helps to maintain the path conveniently in configuration/constant form.

final WebClient webClient = WebClient
.builder()
.baseUrl("http://localhost")
.build();
webClient
.get()
.uri(uriBuilder -> uriBuilder.path("api/v2/json/test").build())
.exchange();