I have 3 models User
, House
, UserHouseMap
. And I need to access a user's house through the map. Only problem is this is an old DB & I can't change the fact that I need to map User
to UserHouseMap
using user.name
, which is a non primary key.
Hibernate keeps giving me errors saying I need to have it as the primary key or I get errors saying A JPA error occurred (Unable to build EntityManagerFactory): Unable to find column with logical name: name in org.hibernate.mapping.Table(users) and its related supertables and secondary tables
I have tried @Formula
as a workaround, but that didnt work. I also tried @JoinColumnOrFormula
but that didnt work either. Here is my solution with @Formula
@Expose @ManyToOne(targetEntity = House.class) @Formula("(select * from houses inner join user_house_map on houses.house_name = user_house_map.house_name where user_house_map.user_name=name)") public House house;
Here was my attempt at a @JoinColumnOrFormula
solution.
@Expose @ManyToOne(targetEntity = House.class) @JoinColumnsOrFormulas({ @JoinColumnOrFormula(formula=@JoinFormula(value="select name from users where users.id= id", referencedColumnName="name")), @JoinColumnOrFormula(column = @JoinColumn(name= "house_name", referencedColumnName="house_name")) }) public House house;
Here is my mapping
@Id @GeneratedValue @Expose public Long id; @Expose @Required @ManyToOne @JoinTable( name="user_house_map", joinColumns= @JoinColumn(unique=true,name="user_name", referencedColumnName="name"), inverseJoinColumns= @JoinColumn(name="house_name", referencedColumnName="house_name")) private House house;
Here are the DB schemas
Users
Table "public.users" Column | Type | Modifiers -----------------------+-----------------------------+----------------------------- name | character varying(255) | id | integer | not null Indexes: "user_pkey" PRIMARY KEY, btree (id) Foreign-key constraints: "housing_fkey" FOREIGN KEY (name) REFERENCES user_house_map(user_name) DEFERRABLE INITIALLY DEFERRED
Houses
Table "public.houses" Column | Type | Modifiers ---------------+------------------------+----------- house_name | character varying(255) | not null address | text | city | text | state | text | zip | integer | zip_ext | integer | phone | text | Indexes: "house_pkey" PRIMARY KEY, btree (house_name) Referenced by: TABLE "user_house_map" CONSTRAINT "house_map_fkey" FOREIGN KEY (house_name) REFERENCES house(house_name) DEFERRABLE INITIALLY DEFERRED
UserHouseMap
Table "public.user_house_map" Column | Type | Modifiers -------------+------------------------+----------- user_name | character varying(255) | not null house_name | character varying(255) | not null Indexes: "user_house_map_pkey" PRIMARY KEY, btree (user_name) "user_house_map_house_key" btree (house_name) Foreign-key constraints: "user_house_map_house_fkey" FOREIGN KEY (house_name) REFERENCES houses(house_name) DEFERRABLE INITIALLY DEFERRED Referenced by: TABLE "users" CONSTRAINT "housing_fkey" FOREIGN KEY (name) REFERENCES user_house_map(user_name) DEFERRABLE INITIALLY DEFERRED
We can apply the Joins in Hibernate by using the HQL query or native SQL query. To make a join between the two tables, the two tables must be in a logical relationship. We can achieve the relationship between two tables by applying the parent table's primary key as a child table's foreign key.
Every JPA entity must have a primary key. You can specify a primary key as a single primitive, or JDK object type entity field (see "Configuring a JPA Entity Simple Primary Key Field").
Not with Hibernate. It requires a primary key.
The usage of the isbn as the foreign key requires an additional @JoinColumn annotation. The referencedColumnName attribute tells Hibernate the name of the database column it shall use as the foreign key.
This is how your mapping should look like:
@Entity public class User { @Id private Long id; private String name; @OneToMany(mappedBy = "user") private List<UserHouseMap> houses = new ArrayList<>(); } @Entity public class House { @Id @Column(name = "house_name", nullable = false, unique = true) private String house_name; private String address; @OneToMany(mappedBy = "house") private List<UserHouseMap> users = new ArrayList<>(); } @Entity public class UserHouseMap implements Serializable { @Id @ManyToOne @JoinColumn(name = "user_name", referencedColumnName = "name") private User user; @Id @ManyToOne @JoinColumn(name = "house_name", referencedColumnName = "house_name") private House house; }
Both User
and House
have access to their associated UserHouseMap
entities, matching the database schema.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With