Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

How to iterate over this n-dimensional dataset?

I have a dataset which has 4 dimensions (for now...) and I need to iterate over it.

To access a value in the dataset, I do this:

value = dataset[i,j,k,l]

Now, I can get the shape for the dataset:

shape = [4,5,2,6]

The values in shape represent the length of the dimension.

How, given the number of dimensions, can I iterate over all the elements in my dataset? Here is an example:

for i in range(shape[0]):
    for j in range(shape[1]):
        for k in range(shape[2]):
            for l in range(shape[3]):
                print('BOOM')
                value = dataset[i,j,k,l]

In the future, the shape may change. So for example, shape may have 10 elements rather than the current 4.

Is there a nice and clean way to do this with Python 3?

like image 979
pookie Avatar asked Aug 17 '17 14:08

pookie


People also ask

Can you iterate over sets?

There is no way to iterate over a set without an iterator, apart from accessing the underlying structure that holds the data through reflection, and replicating the code provided by Set#iterator...

How do you iterate over a list length?

You can loop through the list items by using a while loop. Use the len() function to determine the length of the list, then start at 0 and loop your way through the list items by referring to their indexes. Remember to increase the index by 1 after each iteration.


1 Answers

You could use itertools.product to iterate over the cartesian product 1 of some values (in this case the indices):

import itertools
shape = [4,5,2,6]
for idx in itertools.product(*[range(s) for s in shape]):
    value = dataset[idx]
    print(idx, value)
    # i would be "idx[0]", j "idx[1]" and so on...

However if it's a numpy array you want to iterate over, it could be easier to use np.ndenumerate:

import numpy as np

arr = np.random.random([4,5,2,6])
for idx, value in np.ndenumerate(arr):
    print(idx, value)
    # i would be "idx[0]", j "idx[1]" and so on...

1 You asked for clarification what itertools.product(*[range(s) for s in shape]) actually does. So I'll explain it in more details.

For example is you have this loop:

for i in range(10):
    for j in range(8):
        # do whatever

This can also be written using product as:

for i, j in itertools.product(range(10), range(8)):
#                                        ^^^^^^^^---- the inner for loop
#                             ^^^^^^^^^-------------- the outer for loop
    # do whatever

That means product is just a handy way of reducing the number of independant for-loops.

If you want to convert a variable number of for-loops to a product you essentially need two steps:

# Create the "values" each for-loop iterates over
loopover = [range(s) for s in shape]

# Unpack the list using "*" operator because "product" needs them as 
# different positional arguments:
prod = itertools.product(*loopover)

for idx in prod:
     i_0, i_1, ..., i_n = idx   # index is a tuple that can be unpacked if you know the number of values.
                                # The "..." has to be replaced with the variables in real code!
     # do whatever

That's equivalent to:

for i_1 in range(shape[0]):
    for i_2 in range(shape[1]):
        ... # more loops
            for i_n in range(shape[n]):  # n is the length of the "shape" object
                # do whatever
like image 53
MSeifert Avatar answered Oct 28 '22 01:10

MSeifert