I have an instance of this class:
public class MyClass
{
public string Username { get; set; }
public string Password { get; set; }
public string GetJson()
{
return JsonConvert.SerializeObject(this);
}
}
but in some cases I need more properties in serialized json. I thought I should make a second inherited class like this:
public class MyInheritedClass : MyClass
{
public string Email { get; set; }
}
If I'm not solving the problem in the wrong way, how can I initialize a new instance of my second class with an instance of the first one and have a json string from GetJson()
that contains all the three properties?
Abstract base classes cannot be instantiated. Instead, they are inherited and extended by the concrete subclasses. Subclasses derived from a specific abstract base class must implement the methods and properties provided in that abstract base class.
The class whose members are inherited is called the base class, and the class that inherits those members is called the derived class. A derived class can have only one direct base class. However, inheritance is transitive.
When you initialize a child class in Python, you can call the super(). __init__() method. This initializes the parent class object into the child class. In addition to this, you can add child-specific information to the child object as well.
You can create a constructor in your derived class and map the objects,
public class MyInheritedClass : MyClass
{
MyInheritedClass (MyClass baseObject)
{
this.UserName = baseObject.UserName; // Do it similarly for rest of the properties
}
public string Email { get; set; }
}
MyInheritedClass inheritedClassObject = new MyInheritedClass(myClassObject);
inheritedClassObject.GetJson();
Updated Constructor :
MyInheritedClass (MyClass baseObject)
{
//Get the list of properties available in base class
var properties = baseObject.GetProperties();
properties.ToList().ForEach(property =>
{
//Check whether that property is present in derived class
var isPresent = this.GetType().GetProperty(property);
if (isPresent != null && property.CanWrite)
{
//If present get the value and map it
var value = baseObject.GetType().GetProperty(property).GetValue(baseObject, null);
this.GetType().GetProperty(property).SetValue(this, value, null);
}
});
}
One of the options is to serialize the base class object and then deserialize it to derived class.
E.g. you can use Json.Net serializer
var jsonSerializerSettings = new JsonSerializerSettings
{ //You can specify other settings or no settings at all
PreserveReferencesHandling = PreserveReferencesHandling.Objects,
ReferenceLoopHandling = ReferenceLoopHandling.Ignore
};
string jsonFromBase = JsonConvert.SerializeObject(baseObject, Formatting.Indented, jsonSerializerSettings);
derivedClass= JsonConvert.DeserializeObject<DerivedClass>(jsonFromBase) ;
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