Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

How to initialize data.frame with column of type POSIXct?

I can initialize a data.frame via

df <- data.frame(a=numeric(), b=character())

But how do I define a column of type POSIXct?

df <- data.frame(a=numeric(), b=character(), c=POSIXct())

won't work.

like image 651
JerryWho Avatar asked Jun 16 '14 19:06

JerryWho


2 Answers

You can try

df <- data.frame(a=numeric(), b=character(), c=as.POSIXct(character()))

Similarly, you can create a POSIXct column of NAs in a data frame with > 0 rows by creating a new column with as.POSIXct(NA).

like image 160
konvas Avatar answered Nov 12 '22 09:11

konvas


An additional tip to the above initialization: If you begin rbind() activities to add rows to this empty data frame, you may encounter an error like the following if you follow this pattern:

oneDF <- rbind(oneDF,twoDF,stringsAsFactors=FALSE)
Error in as.POSIXct.default(value) :
  do not know how to convert 'value' to class "POSIXct"

I finally discovered that removing the stringsAsFactors=FALSE allowed for the POSIXct value (both integer time and time zone) to transfer to the target DF.

oneDF <- rbind(oneDF,twoDF)

examining the result:

unclass(oneDF$mytime)
[1] 1282089600
attr(,"tzone")
[1] "GMT"
like image 1
Robert Casey Avatar answered Nov 12 '22 10:11

Robert Casey