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I use utf8 and have to save a constant in a char array:
const char s[] = {0xE2,0x82,0xAC, 0}; //the euro sign
However it gives me error:
test.cpp:15:40: error: narrowing conversion of ‘226’ from ‘int’ to ‘const char’ inside { } [-fpermissive]
I have to cast all the hex numbers to char, which I feel tedious and don't smell good. Is there any other proper way of doing this?
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You can initialize a one-dimensional character array by specifying: A brace-enclosed comma-separated list of constants, each of which can be contained in a character. A string constant (braces surrounding the constant are optional)
To initialize a char in Java, we can use any char value such as an empty char, or \0 , or even a char value itself.
In python, there are inbuilt functions like hex() to convert binary numbers to hexadecimal numbers. To add two hexadecimal values in python we will first convert them into decimal values then add them and then finally again convert them to a hexadecimal value. To convert the numbers make use of the hex() function.
char may be signed or unsigned (and the default is implementation specific). You probably want
const unsigned char s[] = {0xE2,0x82,0xAC, 0};
or
const char s[] = "\xe2\x82\xac";
or with many recent compilers (including GCC)
const char s[] = "€";
(a string literal is an array of char unless you give it some prefix)
See -funsigned-char (or -fsigned-char) option of GCC.
On some implementations a char is unsigned and CHAR_MAX is 255 (and CHAR_MIN is 0). On others char-s are signed so CHAR_MIN is -128 and CHAR_MAX is 127 (and e.g. things are different on Linux/PowerPC/32 bits and Linux/x86/32 bits). AFAIK nothing in the standard prohibits 19 bits signed chars.
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