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Using Initializer List. int arr[] = { 1, 1, 1, 1, 1 }; The array will be initialized to 0 if we provide the empty initializer list or just specify 0 in the initializer list.
No, stuff will be an empty array of strings, not an empty string.
If you are going to use values from the array right after it is created, you want those values to have something. In the absence of further information, 0 is a good starting value. If you are going to use the array only to store values (at the beginning) and you don't really care what's in it, don't initialize.
Global variables and static variables are automatically initialized to zero. If you have simply
char ZEROARRAY[1024];
at global scope it will be all zeros at runtime. But actually there is a shorthand syntax if you had a local array. If an array is partially initialized, elements that are not initialized receive the value 0 of the appropriate type. You could write:
char ZEROARRAY[1024] = {0};
The compiler would fill the unwritten entries with zeros. Alternatively you could use memset to initialize the array at program startup:
memset(ZEROARRAY, 0, 1024);
That would be useful if you had changed it and wanted to reset it back to all zeros.
If you'd like to initialize the array to values other than 0, with gcc you can do:
int array[1024] = { [ 0 ... 1023 ] = -1 };
This is a GNU extension of C99 Designated Initializers. In older GCC, you may need to use -std=gnu99 to compile your code.
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