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char * msg = new char[65546]; want to initialize to 0 for all of them. what is the best way to do this in C++?
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Another useful method to initialize a char array is to assign a string value in the declaration statement. The string literal should have fewer characters than the length of the array; otherwise, there will be only part of the string stored and no terminating null character at the end of the buffer.
Because arrays of characters are ordinary arrays, they follow the same rules as these. For example, to initialize an array of characters with some predetermined sequence of characters, we can do it just like any other array: char myword[] = { 'H' , 'e' , 'l' , 'l' , 'o' , '\0' };
In C++, when you initialize character arrays, a trailing '\0' (zero of type char) is appended to the string initializer. You cannot initialize a character array with more initializers than there are array elements. In ISO C, space for the trailing '\0' can be omitted in this type of information.
char * msg = new char[65546](); It's known as value-initialisation, and was introduced in C++03. If you happen to find yourself trapped in a previous decade, then you'll need to use std::fill() (or memset() if you want to pretend it's C).
Note that this won't work for any value other than zero. I think C++0x will offer a way to do that, but I'm a bit behind the times so I can't comment on that.
UPDATE: it seems my ruminations on the past and future of the language aren't entirely accurate; see the comments for corrections.
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The "most C++" way to do this would be to use std::fill.
std::fill(msg, msg + 65546, 0); If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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