I am trying to convert an AngularJS app to use browserify. I have installed all my bower packages in node_modules using napa. Now I want to browserify them into a separate vendor bundle and declare them as 'external' dependencies. I would like to give them aliases, so that I can "require('angular')" instead of "require('angular/angular')", as it seems you can do with externals.
The examples I have seen (e.g. http://benclinkinbeard.com/posts/external-bundles-for-faster-browserify-builds/) all assume that I have downloaed the vendor files into a 'lib' directory. I want to just bundle my vendor files from node_modules. It seems like it should be easy but I can't see how to do it.
Run the dist/ directory through Browserify to produce a package. bundle. js file and include that as a script tag. This seems to run without error, but the main function I need to instantiate the logic I need isn't present in the browser.
Browserify solves the problems of having too many JS files referenced in your HTML, inability to use Node modules in the browser, and inability to reference your own modules in your own code. Watchify streamlines the process of bundling your files and will make a change every time you change a JS file in your project.
Browserify is an open-source JavaScript bundler tool that allows developers to write and use Node. js-style modules that compile for use in the browser.
I was just trying to do the same thing. I think you need to use --require
for the vendor bundle and --export
for the application's so that the dependencies don't get bundled twice.
This worked for me using browserify's api and gulp (lodash and pixijs being my node_modules):
var gulp = require('gulp'); var browserify = require('browserify'); var handleErrors = require('../util/handleErrors'); var source = require('vinyl-source-stream'); gulp.task('libs', function () { return browserify() .require('lodash') .require('pixi.js') .bundle() .on('error', handleErrors) .pipe(source('libs.js')) .pipe(gulp.dest('./build/')); }); gulp.task('scripts', function () { return browserify('./src/main.js') .external('lodash') .external('pixi.js') .bundle() .on('error', handleErrors) .pipe(source('main.js')) .pipe(gulp.dest('./build/')); }); gulp.task('watch', function(){ gulp.watch('src/**', ['scripts']); }); gulp.task('default', ['libs', 'scripts', 'watch']);
Of course, this solution is a pain to maintain... So I patched browserify to accept arrays in require
and external
and then you can do this which I think it's a lot better:
var gulp = require('gulp'); var browserify = require('browserify'); var handleErrors = require('../util/handleErrors'); var source = require('vinyl-source-stream'); var packageJson = require('../../package.json'); var dependencies = Object.keys(packageJson && packageJson.dependencies || {}); gulp.task('libs', function () { return browserify() .require(dependencies) .bundle() .on('error', handleErrors) .pipe(source('libs.js')) .pipe(gulp.dest('./build/')); }); gulp.task('scripts', function () { return browserify('./src/main.js') .external(dependencies) .bundle() .on('error', handleErrors) .pipe(source('main.js')) .pipe(gulp.dest('./build/')); }); gulp.task('watch', function(){ gulp.watch('package.json', ['libs']); gulp.watch('src/**', ['scripts']); }); gulp.task('default', ['libs', 'scripts', 'watch']);
That's the best I could come up with... Please, let me know if you find a better way.
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