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How to implement my very own URI scheme on Android

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How can I get Android URI scheme?

To start, you need to pick an Activity within your app that you'd like to open when the URI scheme is triggered and register an intent filter for it. Add the following code within the <activity /> tag within your manifest that corresponds to the Activity you want to open.

Where can I find URI app scheme?

Go to the Play store, find the app and view its page. Copy the URL from the browser address bar. Make a note of this as the "Android Fallback URL." You'll see a parameter called "id" followed by an equal sign (=).

What is scheme in Android?

attributes: android:scheme. The scheme part of a URI. This is the minimal essential attribute for specifying a URI; at least one scheme attribute must be set for the filter, or none of the other URI attributes are meaningful. A scheme is specified without the trailing colon (for example, http , rather than http: ).

What is scheme name in URI?

If the URI is telnet://192.0.2.16:80, the scheme name is "telnet."


This is very possible; you define the URI scheme in your AndroidManifest.xml, using the <data> element. You setup an intent filter with the <data> element filled out, and you'll be able to create your own scheme. (More on intent filters and intent resolution here.)

Here's a short example:

<activity android:name=".MyUriActivity">
    <intent-filter>
        <action android:name="android.intent.action.VIEW" />
        <category android:name="android.intent.category.DEFAULT" />
        <category android:name="android.intent.category.BROWSABLE" />
        <data android:scheme="myapp" android:host="path" />
    </intent-filter>
</activity>

As per how implicit intents work, you need to define at least one action and one category as well; here I picked VIEW as the action (though it could be anything), and made sure to add the DEFAULT category (as this is required for all implicit intents). Also notice how I added the category BROWSABLE - this is not necessary, but it will allow your URIs to be openable from the browser (a nifty feature).


Complementing the @DanielLew answer, to get the values of the parameteres you have to do this:

URI example: myapp://path/to/what/i/want?keyOne=valueOne&keyTwo=valueTwo

in your activity:

Intent intent = getIntent();
if (Intent.ACTION_VIEW.equals(intent.getAction())) {
  Uri uri = intent.getData();
  String valueOne = uri.getQueryParameter("keyOne");
  String valueTwo = uri.getQueryParameter("keyTwo");
}

I strongly recommend that you not define your own scheme. This goes against the web standards for URI schemes, which attempts to rigidly control those names for good reason -- to avoid name conflicts between different entities. Once you put a link to your scheme on a web site, you have put that little name into entire the entire Internet's namespace, and should be following those standards.

If you just want to be able to have a link to your own app, I recommend you follow the approach I described here:

How to register some URL namespace (myapp://app.start/) for accessing your program by calling a URL in browser in Android OS?


Another alternate approach to Diego's is to use a library:

https://github.com/airbnb/DeepLinkDispatch

You can easily declare the URIs you'd like to handle and the parameters you'd like to extract through annotations on the Activity, like:

@DeepLink("path/to/what/i/want")
public class SomeActivity extends Activity {
  ...
}

As a plus, the query parameters will also be passed along to the Activity as well.